我正在为我的网站制作注册表单。
我的注册表单上的一个字段是一个下拉框，由我的 MySQL 数据库上的一个表填充。
我最初以不同的方式编写了注册脚本，但我需要更改表单的工作方式以适应新的下拉框以及它收集数据的方式。
在更改之前表单已成功提交，但现在它只是给了我一个白屏。
我已经用 if-else 语句检查了 mysqli_connect.php。它表明它正在工作，但在按下提交按钮时没有向 MySQL 服务器发送注册。此外，下拉框没有显示它链接到的 MySQL 表中的任何内容。
下面是我正在使用的脚本的副本：
<?php
@ini_set('display_errors', 'on');
echo "<h1>Register</h1>";
if ($_SERVER['REQUEST_METHOD'] == 'POST'){
$errors = array();
if (empty($_POST['firstname'])){
$errors[] = 'Your forgot to enter your first name.';
}else{
$firstname = trim($_POST['firstname']);
}
if (empty($_POST['lastname'])){
$errors[] = 'Your forgot to enter your last name.';
}else{
$lastname = trim($_POST['lastname']);
}
if (empty($_POST['username'])){
$errors[] = 'Your forgot to enter your username.';
}else{
$username = trim($_POST['username']);
}
if (!empty($_POST['password1'])) {
if ($_POST['password1'] != $_POST ['password2']) {
$errors[] = 'Your password did not match the confirmed password!';
}else{
$password = trim($_POST['password1']);
}
} else {
$errors[] = 'You forgot to enter your password!';
}
if (empty($_POST['birthdate'])){
$errors[] = 'Your forgot to enter your birthdate.';
}else{
$birthdate = trim($_POST['birthdate']);
}
if (empty($_POST['gamespyid'])){
$errors[] = 'Your forgot to enter your gamespy id.';
}else{
$gamespyid = trim($_POST['gamespyid']);
}
if (empty($errors)) {
require ('mysqli_connect.php');
$q="INSERT INTO Users (firstname, lastname, username, password1, birthdate, gamespyid, base) VALUES ('$firstname', '$lastname', '$username', SHA1('$password1'), '$birthdate', '$gamespyid', '$base')";
$r = @mysql_query($dbc, $q);
if ($r){
echo'<p>You are now registered</p>';
}else{
echo'<p>You have not been registered</p>';
}
} else {
echo 'Error<br> <p>The following errors have occured:<br/>';
foreach ($error as $msg) {
echo " - $msg<br/>\n";
}
echo '</p><p>Please try again.</p><p><br/></p>';
} //if no errors
} //submit
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 3.2//EN">
<html>
<head>
<title></title>
</head>
<body>
<form action="../pages/register.inc.php" method='POST'>
<table summary="REgform">
<tr>
<td>First Name:</td>
<td><input type='text' name='firstname' value='<?php echo $firstname; ?>'></td>
</tr>
<tr>
<td>Last Name:</td>
<td><input type='text' name='lastname'value='<?php echo $lastname; ?>'></td>
</tr>
<tr>
<td>Username:</td>
<td><input type='text' name='username'value='<?php echo $username; ?>'></td>
</tr>
<tr>
<td>Password:</td>
<td><input type='password' name='password1'></td>
</tr>
<tr>
<td>Repeat Password:</td>
<td><input type='password' name='password2'></td>
</tr>
<tr>
<td>Birthdate:</td>
<td><input type='text ' name='birthdate'value='<?php echo $birthdate; ?>'></td>
</tr>
<tr>
<td>Gamespy Id:</td>
<td><input type='text' name='gamespyid'value='<?php echo $gamespyid; ?>'></td>
</tr>
<tr>
<td>Base:</td>
<td><select name="base" size="1">
<option>
Select One
</option>
<?php require('http://www.virtual-aviation.org/gatewayaviation/admin/mysqli_connect.php');
$q = "SELECT id, CONCAT_WS(' ', airport_name, airport_code) FROM airports ORDER BY airport_code ASC";
$r = mysqli_query ($dbc, $q);
if (mysqli_num_rows($r) > 0) {
while ($row = mysql_fetch_array ($r, MYSQL_NUM)) {
echo "<option value=\"$row[0]\"";
if (isset($_POST['existing']) && ($_POST['existing'] == $row[0]) ) echo 'selected="selected"'; echo ">$row[1]</option>\n";
}
} else {
echo '<option>Please a new airport first.</optioon>';
}
mysqli_close($dbc);
?>
</select></td>
</tr>
</table>
<p><input type='submit' name='submit' value='Register'></p>
</form>
</body>
</html>
在下拉框区域中发现错误
警告：mysqli_query() 期望参数 1 为 mysqli，在第178行的/home5/virtua15/public_html/gatewayaviation/pages/register.inc.php中给出 null警告：mysqli_num_rows() 期望参数 1 为是 mysqli_result，在第180行的/home5/virtua15/public_html/gatewayaviation/pages/register.inc.php中给出的 null 请先换
一个新机场。