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static class QueryableExtensions
{
private static MethodInfo StringContainsMethod;
private static MethodInfo StringStartsWithMethod;
static QueryableExtensions()
{
    Type[] singleStringParam = new[] { typeof(string) };
    StringContainsMethod = typeof(string).GetMethod("Contains", singleStringParam);
    StringStartsWithMethod = typeof(string).GetMethod("StartsWith", singleStringParam);
}
public static IQueryable<T> AppendTextFilter<T>(this IQueryable<T> queryable, Expression<Func<T, string>> memberSelector, string condition, string value)
{
    Expression expression = null;
    switch (condition)
    {
        case "StartsWith":
            expression = Expression.Call(memberSelector.Body, StringStartsWithMethod, Expression.Constant(value));
            break;
        case "Equals":
            expression = Expression.Equal(memberSelector.Body, Expression.Constant(value));
            break;
        case "Contains":
            expression = Expression.Call(memberSelector.Body, StringContainsMethod, Expression.Constant(value));
            break;
        default:
            throw new NotSupportedException(string.Format("'{0}' is not a supported condition", condition));
    }
    var lambda = Expression.Lambda<Func<T, bool>>(expression, memberSelector.Parameters);
    return queryable.Where(lambda);
}
}

当我在谷歌上搜索时,我得到了上面的类。嗯,它真的帮了我很多,但它仍然不能满足我的需要。
问题是它只能处理“字符串”类型的字段。正如您在上面的代码块中看到的,该方法只能处理 T,string 。
我如何在一个方法中处理我想要的任何类型?

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1 回答 1

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好吧,这个想法是用泛型类型替换字符串,这种方式。

public static IQueryable<T> AppendTextFilter<T, TValue>(
      this IQueryable<T> queryable, 
      Expression<Func<T, TValue>> memberSelector, 
      string condition, 
      TValue value)

但是对于您的示例,这没有多大意义,StartsWith例如,如果TValuetype 为 string...

于 2012-07-20T07:59:54.897 回答