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我想使用 echo 和 $_SESSION 一次使用一个 div。当我把它放到网上时，它只显示 $form。你能看看我做错了什么吗？

    $signedIn ='<h3 id="throughHeader"> Account options</h3><br/>
        <p id="throughP"> <a href="convenientaccountinfo.php> Account Info </a></p><br/>
        <p id="throughP"><a href="convenientaddaddress.php> Add Address </a></p><br/>
        <p id="throughP"> <a href="convenientaddcreditcard.php> Add C. Card </a></p><br/>
        <p id="throughP"> <a href="convenientsignout.php> Sign Out </a></p>';


        $form='<form id="signInForm" method="POST" action=""><h3 id="formHeader">Sign Into Account</h3><br/>
        <p id="pRegister"><a id="register" href="convenientregisterpage.php"> Register </a></p><br/>
        <label>Email Addr:</label><input type="text" name="userEmail" id="email" size="15"/><br/>
        <label>Password:</label><input type="password" name="password" id="password" size="15"/><br/>
        <input type="submit" value="Sign In" id="formSubmit" name="submit"/> </form>';

    $username = $_SESSION['userEmail'];
    if(!$username){
        $signedInForm="$form";
    }
    else{
        $signedInForm="$signedIn";
    }
}

这是带有验证的 POST 表单，直到它设置了 $_SESSION。感谢您再次查看它。

 $email=$_POST['userEmail'];
$password=$_POST['password'];
if(isset($_POST['submit'])){
    if(empty($email) || empty($password)){
    $msg_to_user3="Fill in both fields";
    }
    else{
    $results=mysql_query("SELECT * FROM register WHERE userEmail='$email'");
   if (mysql_num_rows($results)==0)
       $msg_to_user3 ="No such User";
    else
    {
      while ($login_row = mysql_fetch_assoc($results))
      {
       $password_db = $login_row['password'];
       if ($password!=$password_db){
         $msg_to_user3 ="Password doesn't match";
       }
         if ($password_db!=$password){

        $msg_to_user2="<a id='forgetpassword' href='convenientforgotpassword.php'>Forget Password</a>";
     }
       else
       {
          $active = $login_row['active'];
          $userEmail = $login_row['userEmail'];
          if ($active==0){
             $msg_to_user3= "Activate account at ($userEmail) </p>";
      }
         else
          { 
           $_SESSION['userEmail']=$username;//assign session
      }

      }
      }
    }
       }
}   
<html>
    <body>
    <div id="formSignIn">
        <?php echo $signedInForm ;?>
        </div>
    </body>
    </htmo>
4

1 回答 1

0

好的，我得到了 $_SESSION 工作，它在 $form 和 $signedIn 变量之间切换。至于两个只显示 ps 我把 id 去掉了，在 a href 中引号没有关闭，所以它没有关闭每个链接。感谢你的帮助！！

于 2012-07-22T02:17:38.407 回答