2

我将 MVC 3 与 View Model 一起使用，在我的情况下，我有一个 View Model，它应该显示一个项目列表以及一个用于插入一些输入的表单。

我的视图有问题，因为我无法将用于插入数据的表单与视图模型相关联，你能告诉我我做错了什么吗？

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.ComponentModel.DataAnnotations;
using TestGuestBook.Models;

namespace TestGuestBook.ViewModel
{
    public class ListAddCommentsViewModel
    {
        public int CommentId { get; set; }

        [Required]
        public string Nominative { get; set; }

        [Email]
        public string Email { get; set; }

        [Required]
        public string Content { get; set; }

        public List<Comment> CommentItems { get; set; }
    }
}

看法

@model IEnumerable<TestGuestBook.ViewModel.ListAddCommentsViewModel>

@{
    ViewBag.Title = "Index";
}

<h2>Index</h2>

@using (Html.BeginForm()) {
    @Html.ValidationSummary(true)
    <fieldset>
        <legend>ListAddCommentsViewModel</legend>

        <div class="editor-label">
            @Html.LabelFor(model => model.CommentId)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.CommentId)
            @Html.ValidationMessageFor(model => model.CommentId)
        </div>

        <div class="editor-label">
            @Html.LabelFor(model => model.Nominative)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.Nominative)
            @Html.ValidationMessageFor(model => model.Nominative)
        </div>

        <div class="editor-label">
            @Html.LabelFor(model => model.Email)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.Email)
            @Html.ValidationMessageFor(model => model.Email)
        </div>

        <div class="editor-label">
            @Html.LabelFor(model => model.Content)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.Content)
            @Html.ValidationMessageFor(model => model.Content)
        </div>

        <p>
            <input type="submit" value="Create" />
        </p>
    </fieldset>
}

<p>
    @Html.ActionLink("Create New", "Create")
</p>
<table>
    <tr>
        <th>
            CommentId
        </th>
        <th>
            Nominative
        </th>
        <th>
            Email
        </th>
        <th>
            Content
        </th>
        <th></th>
    </tr>

@foreach (var item in Model) {
    <tr>
        <td>
            @Html.DisplayFor(modelItem => item.CommentId)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Nominative)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Email)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Content)
        </td>
        <td>
            @Html.ActionLink("Edit", "Edit", new { /* id=item.PrimaryKey */ }) |
            @Html.ActionLink("Details", "Details", new { /* id=item.PrimaryKey */ }) |
            @Html.ActionLink("Delete", "Delete", new { /* id=item.PrimaryKey */ })
        </td>
    </tr>
}

</table>
4

2 回答 2

9

您不需要将 a 传递Collection给您的视图。ViewModel 的一个对象就足够了。您ViewModel已经拥有收藏收藏品的财产（清单Comments）

因此，在您的GETAction 中，仅将此 viewModel 的一个实例返回给 View

public ActionResult GetComments(int postId)
{
  var viewModel=new ListAddCommentsViewModel();
  viewModel.CommentItems =db.GetComments(postId);
  return View(viewModel);
}

现在在您的视图中，让它绑定到单个实例ListAddCommentsViewModel

@model TestGuestBook.ViewModel.ListAddCommentsViewModel

在您的视图中，要显示您的评论列表，Model.CommentItems请在您的ViewModel

@foreach (var item in Model.CommentItems) {
    <tr>
        <td>
            @Html.DisplayFor(modelItem => item.CommentId)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Nominative)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Email)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Content)
        </td>
        <td>
            @Html.ActionLink("Edit", "Edit", new {  @id=item.PrimaryKey  }) |
            @Html.ActionLink("Details", "Details", new {  @id=item.PrimaryKey  }) |
            @Html.ActionLink("Delete", "Delete", new { @id=item.PrimaryKey  })
        </td>
    </tr>
}
于 2012-07-19T19:15:38.700 回答
0

这是最好的解决方案，我检查了几乎所有信息，这是一个有效的解决方案！谢谢

    public  ActionResult UploadFile(UploadFileViewModel model)
    {
        if (ModelState.IsValid)
        {
            var file = model.File;
            var parsedContentDisposition =
            ContentDispositionHeaderValue.Parse(file.ContentDisposition);
            var filename = Path.Combine(_environment.WebRootPath,
                "Uploads", parsedContentDisposition.FileName.Trim('"'));
            file.SaveAsAsync(filename);
        }

        return View();
    }
于 2016-05-12T06:18:31.030 回答