在 Windows 应用程序 (Visual Studio)(VB) 中,如何将单行拖放到另一个位置以允许用户重新排序该行?我还没有找到任何有价值的例子。
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5 回答
8
这是来自此 C# 答案的 vb 版本:如何将 DataGridView 行拖放到彼此下方?
表单类变量:
Private fromIndex As Integer
Private dragIndex As Integer
Private dragRect As Rectangle
拖动事件:
Private Sub DataGridView1_DragDrop(ByVal sender As Object, _
ByVal e As DragEventArgs) _
Handles DataGridView1.DragDrop
Dim p As Point = DataGridView1.PointToClient(New Point(e.X, e.Y))
dragIndex = DataGridView1.HitTest(p.X, p.Y).RowIndex
If (e.Effect = DragDropEffects.Move) Then
Dim dragRow As DataGridViewRow = e.Data.GetData(GetType(DataGridViewRow))
DataGridView1.Rows.RemoveAt(fromIndex)
DataGridView1.Rows.Insert(dragIndex, dragRow)
End If
End Sub
Private Sub DataGridView1_DragOver(ByVal sender As Object, _
ByVal e As DragEventArgs) _
Handles DataGridView1.DragOver
e.Effect = DragDropEffects.Move
End Sub
鼠标事件:
Private Sub DataGridView1_MouseDown(ByVal sender As Object, _
ByVal e As MouseEventArgs) _
Handles DataGridView1.MouseDown
fromIndex = DataGridView1.HitTest(e.X, e.Y).RowIndex
If fromIndex > -1 Then
Dim dragSize As Size = SystemInformation.DragSize
dragRect = New Rectangle(New Point(e.X - (dragSize.Width / 2), _
e.Y - (dragSize.Height / 2)), _
dragSize)
Else
dragRect = Rectangle.Empty
End If
End Sub
Private Sub DataGridView1_MouseMove(ByVal sender As Object, _
ByVal e As MouseEventArgs) _
Handles DataGridView1.MouseMove
If (e.Button And MouseButtons.Left) = MouseButtons.Left Then
If (dragRect <> Rectangle.Empty _
AndAlso Not dragRect.Contains(e.X, e.Y)) Then
DataGridView1.DoDragDrop(DataGridView1.Rows(fromIndex), _
DragDropEffects.Move)
End If
End If
End Sub
确保将 gridsAllowDrop
属性设置为 true。
于 2012-07-19T20:50:11.103 回答
4
更新:
代替
If dragIndex < 0 Then dragIndex = DataGridView1.RowCount - 1
改成
If dragIndex > -1 Then
'action if not selected in the row header and blank space
else
'return error if selected in the column header and blank space
end if
那么当你将一行拖到“空白区域”时就会出现错误,如果你不相信我,你必须尝试一下。
最终代码(仅适用于“拖动事件”部分)是这样的:
Private Sub DataGridView1_DragDrop(ByVal sender As Object, ByVal e As DragEventArgs) Handles DataGridView1.DragDrop
Dim p As Point = DataGridView1.PointToClient(New Point(e.X, e.Y))
dragIndex = DataGridView1.HitTest(p.X, p.Y).RowIndex
'Determine if dragindex is valid row index
If dragIndex > -1 Then
If (e.Effect = DragDropEffects.Move) Then
Dim dragRow As DataGridViewRow = CType(e.Data.GetData(GetType(DataGridViewRow)), DataGridViewRow)
DataGridView1.Rows.RemoveAt(fromIndex)
DataGridView1.Rows.Insert(dragIndex, dragRow)
'Add this line of code if you want to put selected rows to the rows that change
DataGridView1.Rows(dragIndex).Selected = True
End If
Else 'Do any message here if selected in column header and blank space.
End If
End Sub
于 2014-05-11T06:47:10.013 回答
1
事件GridView.DragDrop的 1.5 改进:
前 50% 的改进,为了避免描述的错误,您也可以使用
Private Sub DgvSearchFieldCurrent_DragDrop( _ ByVal sender As Object, ByVal e As DragEventArgs) _ Handles DgvSearchFieldCurrent.DragDrop Dim LclDgv As DataGridView = CType(sender, DataGridView) If dragIndex > -1 AndAlso dragIndex < LclDgv.RowCount -1 Then
二是将焦点设置到当前行和第一个单元格:
LclDgv.Rows.Insert(dragIndex, dragRow) LclDgv.Rows(fromIndex).Selected = False LclDgv.Rows(dragIndex).Selected = True For Each C As DataGridViewColumn In LclDgv.Columns LclDgv(C.Index, fromIndex).Selected = False Next LclDgv(0, dragIndex).Selected = True
于 2017-06-27T13:25:56.183 回答
1
这是一个没有提到的错误的控件。
在 Windows 窗体设计器中设置AllowUserToOrderRows
和AllowDrop
到True
并拖动行标题,而不是内容。
Imports System.ComponentModel
Public Class BetterDataGridView
Inherits DataGridView
<Category("Behavior"), DefaultValue(False)>
Public Property AllowUserToOrderRows As Boolean = False
Protected Overrides Sub OnMouseDown(e As MouseEventArgs)
MyBase.OnMouseDown(e)
Dim hitInfo As HitTestInfo = HitTest(e.X, e.Y)
If AllowUserToOrderRows AndAlso
e.Button = MouseButtons.Left AndAlso
hitInfo.ColumnIndex = -1 AndAlso
ValidRow(hitInfo.RowIndex) Then
DoDragDrop(Rows(hitInfo.RowIndex), DragDropEffects.Move)
End If
End Sub
Protected Overrides Sub OnDragOver(e As DragEventArgs)
MyBase.OnDragOver(e)
Dim dragRow As DataGridViewRow = e.Data.GetData(GetType(DataGridViewRow))
Dim targetIndex As Integer = GetRowIndex(e)
e.Effect = If(ValidRowDragDrop(dragRow, targetIndex),
DragDropEffects.Move,
DragDropEffects.None)
End Sub
Protected Overrides Sub OnDragDrop(e As DragEventArgs)
MyBase.OnDragDrop(e)
Dim dragRow As DataGridViewRow = e.Data.GetData(GetType(DataGridViewRow))
Dim targetIndex As Integer = GetRowIndex(e)
If e.Effect = DragDropEffects.Move AndAlso ValidRowDragDrop(dragRow, targetIndex) Then
EndEdit()
Rows.Remove(dragRow)
Rows.Insert(targetIndex, dragRow)
ClearSelection()
dragRow.Selected = True
End If
End Sub
Protected Function ValidRow(rowIndex As Integer) As Boolean
Return rowIndex >= 0 AndAlso
rowIndex < Rows.Count - If(AllowUserToAddRows, 1, 0)
End Function
Protected Function GetRowIndex(e As DragEventArgs) As Integer
Dim clientPos As Point = PointToClient(New Point(e.X, e.Y))
Return HitTest(clientPos.X, clientPos.Y).RowIndex
End Function
Protected Function ValidRowDragDrop(dragRow As DataGridViewRow, targetIndex As Integer) As Boolean
Return dragRow IsNot Nothing AndAlso
ValidRow(targetIndex) AndAlso
targetIndex <> dragRow.Index AndAlso
Rows.Contains(dragRow)
End Function
End Class
于 2016-09-30T20:16:36.310 回答
0
谢谢你所做的一切,代码工作。我只得到一个错误。我解决了。
如果设置了 datagridview “启用编辑”,则在抛出行距时会收到错误消息。你可以试试。我解决了如下:
Private Sub DataGridView1(ByVal sender As Object, ByVal e As DragEventArgs) Handles DataGridView1.DragDrop
Dim p As Point = DataGridView1.PointToClient(New Point(e.X, e.Y))
dragIndex = DataGridView1.HitTest(p.X, p.Y).RowIndex
If (e.Effect = DragDropEffects.Move) Then
Dim dragRow As DataGridViewRow = CType(e.Data.GetData(GetType(DataGridViewRow)), DataGridViewRow)
If dragIndex = DataGridView1.RowCount - 1 Then '**ADD THIS AREA**
DataGridView1.Rows.RemoveAt(fromIndex)
DataGridView1.Rows.Insert(DataGridView1.RowCount - 1, dragRow)
Else
If dragIndex < 0 Then dragIndex = DataGridView1.RowCount - 2 '**this is important**
DataGridView1.Rows.RemoveAt(fromIndex)
DataGridView1.Rows.Insert(dragIndex, dragRow)
End If
End If
End Sub
感谢所有其他信息
于 2015-08-12T16:03:36.290 回答