SELECT users.mail, users.name FROM members
LEFT JOIN users ON (users.uid = members.uid) WHERE members.group = 27
AND members.uid NOT IN (SELECT subgroup_members.uid FROM subgroup_members
LEFT JOIN subgroups ON (subgroups.id = subgroup_members.sid)
LEFT JOIN users on (users.uid = subgroup_members.uid) WHERE subgroups.oid = 27 AND subgroup_members.leader = 1)
此查询返回不是子组领导的组的所有成员。
members 表显示哪些userid(uid)
属于 a group(group)
,该subgroup_members
表显示哪些用户属于 a subgroup(sid)
。领导在 subgroup_members 表的领导列中用“1”表示。
我试图弄清楚如何返回一个组中不是唯一领导者的所有成员,我现在很困惑。
所以不是subgroup_members.leader = 1
我需要确定它是否是唯一的价值