我正在尝试建立一个包含 jQuery 和 jTable 的网站。因此,我一直在尝试使用网站提供的示例 jTable 脚本,但似乎无法返回任何输入。文件路径都有效,我检查以确保 jQuery 已加载(确实如此)。我真的不确定我做错了什么,如果有的话。谢谢!
jTable 文件:
<html>
<head>
<link href="JQueryUI/css/smoothness/jquery-ui-1.8.21.custom.css" rel="stylesheet" type="text/css" />
<script type="text/javascript" src="jquery.js"></script>
<link href="jtable/themes/standard/blue/jtable_blue.css" rel="stylesheet" type="text/css" />
<script type="text/javascript" src="jtable/jquery.jtable.js"></script>
</head>
<title>Under Construction</title>
Hello World
<div id="PersonTableContainer"></div>
<script type="text/javascript">
$(document).ready(function () {
$('#PersonTableContainer').jtable({
title: 'Table of people',
actions: {
listAction: 'PersonList.php'
createAction: 'CreatePerson.php'
updateAction: 'UpdatePerson.php'
deleteAction: 'DeletePerson.php'
},
fields: {
PersonId: {
key: true,
create: false,
edit: false,
list: false
},
Name: {
title: 'Author Name',
width: '40%'
},
Age: {
title: 'Age',
width: '20%'
},
RecordDate: {
title: 'Record date',
width: '30%',
type: 'date',
create: false,
edit: false
}
}
});
$('#PersonTableContainer').jtable('load');
});
个人列表.php
<?php
$link = new mysqli("localhost", "user", "pass", "people");
$query = "SELECT * FROM people";
$results = mysqli_query($link, $query);
$rows = array();
while($row = mysqli_fetch_assoc($results))
{
$rows[] = $row;
}
$jTableResult = array();
$jTableResult['Result'] = "OK";
$jTableResult['Records'] = $rows;
print json_encode($jTableResult);
}
?>
PersonList.php 在终端中返回正确的输出,它似乎没有在网站/jTable 中显示任何内容。