1

我为用户的帖子制作了一个简单的 Ajax 投票脚本:+ 1 和 -1。一切正常,但有时由于某种原因一键发送数据 +3、+6、-2 等。我制作了 Chrome 开发人员工具的屏幕截图。可见,一键多次调用PHP脚本。dot.gif - 发送数据时的热闹动画。在此处输入图像描述

<script type="text/javascript" src="raitings/jquery.js"></script>
<script type="text/javascript">$(function() {$(".vote").click(function() {

var id = $(this).attr("id");
var name = $(this).attr("name");
var dataString = 'id='+ id ;
var parent = $(this);

if(name=='down')
{
$(this).fadeIn(200).html('<img src="raitings/dot.gif" align="absmiddle">');
$.ajax({type: "POST", url: "raitings/down_vote.php", data: dataString, dataType : "html", cache: false, success: function(html)
   { parent.html(html);}
 });
}
else
{
$(this).fadeIn(200).html('<img src="raitings/dot.gif" align="absmiddle">');
$.ajax({type: "POST", url: "raitings/up_vote.php", data: dataString, dataType : "html", cache: false, success: function(html)
   { parent.html(html);
  }  });
}
return false;
    });
});
</script>

<?php
echo "<div class=\"box1\"><div class=\"up\"><a href=\"#\" class=\"vote\" title=\"+ 1\" alt=\"+ 1\" id=".$row["id"]." name=\"up\">".$up."</a></div>"
."<div class=\"down\"><a href=\"#\" class=\"vote\" title=\"- 1\" alt=\"- 1\"  id=".$row["id"]." name=\"down\">".$down."</a></div></div>\n";
4

2 回答 2

1

当用户投票后,您应该禁用您的控件。所以只需添加一些阻塞标志(变量、cookie 等):

$(function() {
var isUserVoted = false;
$(".vote").click(function() {
   if (isUserVoted) {
       return false;
   }

   isUserVoted = true;
   var id = $(this).attr("id");
   var name = $(this).attr("name");
   var dataString = 'id='+ id ;
   var parent = $(this);

   if(name=='down') {
      $(this).fadeIn(200).html('<img src="raitings/dot.gif" align="absmiddle">');
      $.ajax({type: "POST", url: "raitings/down_vote.php", data: dataString, dataType : "html", cache: false, success: function(html)
   { parent.html(html);}
      });
   } else {
      $(this).fadeIn(200).html('<img src="raitings/dot.gif" align="absmiddle">');
      $.ajax({type: "POST", url: "raitings/up_vote.php", data: dataString, dataType : "html", cache: false, success: function(html) { parent.html(html);
  }  });
   }
   return false;
});
});
于 2012-07-19T08:34:29.213 回答
-1

而是在 jquery 点击事件上尝试写 onclick="function_name();" 对于一个href..

例如...

于 2012-07-19T08:42:47.013 回答