6

我有一台服务器，我正在尝试构建一个发布请求以取回数据。我认为实现这一点的一种方法是在标头中添加参数并发出请求。但是我遇到了一些我不太了解的错误，无法继续前进。

HTML 表单

<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=ISO-8859-1">
  </head>
  <body>
     <form method="POST" action="http://some.server.com:61235/imgdigest" enctype="multipart/form-data">
        quality:<input type="text" name="quality" value="2"><br>
        category:<input type="text" name="category" value="1"><br>
        debug:<input type="text" name="debug" value="1"><br>
        image:<input type="file" name="image"><br>
        <input type="submit" value="Submit">
     </form>
  </body>
</html>

Python代码：我根据答案编辑了问题

import urllib, urllib2
import base64

if __name__ == '__main__':
    page = 'http://some.site.com:61235/'
    with open("~/image.jpg", "rb") as image_file:
        encoded_image = base64.b64encode(image_file.read())
    raw_params = {'quality':'2','category':'1','debug':'0', 'image': encoded_image}
    params = urllib.urlencode(raw_params)
    request = urllib2.Request(page, params)
    request.add_header("Content-type", "application/x-www-form-urlencoded; charset=UTF-8")
    page = urllib2.urlopen(request)
    info = page.info()

错误：

    page = urllib2.urlopen(request)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 406, in open
    response = meth(req, response)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 519, in http_response
    'http', request, response, code, msg, hdrs)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 444, in error
    return self._call_chain(*args)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 378, in _call_chain
    result = func(*args)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 527, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 404: Not Found
4

1 回答 1

5

添加一个这个标题：

request.add_header("Content-type", "application/x-www-form-urlencoded; charset=UTF-8")

此外，您发送的图像参数是一个字符串，而不是图像文件的内容。您需要对其进行 b64 编码

import base64

with open("image.jpg", "rb") as image_file:
    encoded_image = base64.b64encode(image_file.read())

然后用' 'encoded_image代替~/image.jpgraw_params

于 2012-07-19T20:53:26.530 回答