1

标题中引用的错误（显然）发生在第 33 行。作为旁注，如果您对我可以优化它的方法有任何建议，或者只是一般性建议，我会全力以赴。谢谢！

这是代码：

<?php
error_reporting(E_ALL);
require('config.php');

$filename = htmlentities($_FILES['file']['name']);
$tmpname = $_FILES['file']['tmp_name'];
$filesize = $_FILES['file']['size'];
$filetype = $_FILES['file']['type'];    
$file = $_FILES['file'];

class connect {

    public function dbConnect($host, $user, $pass, $dbname) {

        try {
            global $dbcon;
            $dbcon = new PDO("mysql:host=$host;dbname=$dbname", $user, $pass);
        }
        catch (PDOException $e) {
            print $e->getMessage();
        }
    }
}

class upload Extends connect {
    public function uploadFile($dbcon, $filename, $filesize, $filetype, $file) {

        if ($filesize > 2000000) {
            echo "File too large!";
        }
        elseif ($filesize <= 2000000) {
            $stmt = $dbcon->prepare("INSERT INTO upload (name, type, size, content) VALUES (?, ?, ?, ?)");
            $stmt->$dbcon->bindParam(1, $filename);
            $stmt->$dbcon->bindParam(2, $filetype);
            $stmt->$dbcon->bindParam(3, $filesize);
            $stmt->$dbcon->bindParam(4, $file);
            $stmt->$dbcon->execute();
            $stmt->$dbcon->close();
            echo "File uploaded!";
        }
        else {
            echo "Unexpected error! Please try again!";
        }
    }
}
$con = new connect;
$con->dbConnect($host, $user, $pass, $dbname);

$exec = new upload;
$exec->uploadFile($dbcon, $filename, $filesize, $filetype, $file);
4

1 回答 1

5

你应该使用：

$stmt->bindParam();

从. $dbcon_$stmt->$dbcon->bindParam()

于 2012-07-18T19:30:43.283 回答