我有这样的 XML
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="do.xsl"?>
<catalog>
<cd>
<title_>Empire Burlesque</title_>
<artist>Bobby</artist>
<company>Columbia</company>
</cd>
<cd>
<title_>Shirt2</title_>
<artist>Bobby</artist>
<company>Columbia2</company>
</cd>
<cd>
<title_>Fingers</title_>
<artist>Bobby</artist>
<company>Columbia3</company>
</cd>
<cd>
<title_>Zip1</title_>
<artist>Bobby</artist>
<company>---</company>
</cd>
<cd>
<title_>Zip2</title_>
<artist>Bobby</artist>
<company>---</company>
</cd>
</catalog>
我需要用以前有意义的数据替换 --- Columbia3 我接下来要做
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" version="4.0" encoding="utf-8" indent="yes"/>
<xsl:template match="/">
<html>
<body>
<h2>My CD Collection</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Title</th>
<th>Artist</th>
</tr>
<xsl:for-each select="catalog/cd">
<tr>
<td><xsl:value-of select="title_"/></td>
<td><xsl:value-of select="artist"/></td>
<td>
<xsl:variable name="NotStarted" select="preceding-sibling::cd[1]/company" />
<xsl:choose>
<xsl:when test="company != '---'">
<xsl:value-of select="company"/>
</xsl:when>
<xsl:otherwise>
<xsl:copy-of select="$NotStarted" />
</xsl:otherwise>
</xsl:choose>
</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
正如预期的那样,我得到了下一个 html
Title Artist
Empire Burlesque Bobby Columbia
Shirt2 Bobby Columbia2
Fingers Bobby Columbia3
Zip1 Bobby Columbia3
Zip2 Bobby ---
我如何迭代以获取最后一个有意义的字符串来替换或任何其他方式?谢谢。