4

这是我到目前为止的查询，用于创建每日柱：

SELECT DISTINCT date_trunc('hour',t) AS date,
min(price) OVER w,
max(price) OVER w,
first_value(price) OVER w,
last_value(price) OVER w
FROM ticker
WINDOW w AS (PARTITION BY date_trunc('hour',t));

将“小时”更改为“分钟”或“天”会给我对应于这些单位的条形图。

但是，如果我想要 5 分钟或 15 分钟的酒吧怎么办？date_trunc()不支持这些，我正在寻找一种优雅的方式来做到这一点。

4

1 回答 1

7

以 15 分钟为间隔，以您的示例为基础：

SELECT DISTINCT
     , date_trunc('hour', t) AS h
     , floor(EXTRACT(minute FROM t) / 15) AS m15
     , min(price) OVER w
     , max(price) OVER w
     , first_value(price) OVER w
     , last_value(price) OVER w
FROM   ticker
WINDOW w AS (PARTITION BY date_trunc('hour', t)
                        , floor(extract(minute FROM t) / 15));

也可以工作 5 分钟。

对于任何定期时间间隔、任何时间段的更通用的解决方案：

WITH x AS (
    SELECT t1, t1 + interval '5min' AS t2
    FROM   generate_series(timestamp '2012-07-18 00:00'
                         , timestamp '2012-07-18 23:55'
                         , interval '5 min') AS t1
    )
SELECT DISTINCT ON (1)
       x.t1
     , min(price)         OVER w
     , max(price)         OVER w
     , first_value(price) OVER w
     , last_value(price)  OVER w
FROM   x
JOIN   ticker y ON y.t >= x.t1  -- use LEFT JOIN to include empty intervals
               AND y.t <  x.t2  -- don't use BETWEEN
WINDOW w AS (PARTITION BY x.t1)
ORDER  BY x.t1;

更多解释的相关答案：

于 2012-07-18T03:17:37.537 回答