image - 不重复 xcode 的随机图像生成器

Question

我将如何创建一个随机图像生成器，它不会重复图像，直到它通过它们一次？

例如：

-（IBAction）随机图像按钮 {

int randomimages = rand() % 5;

switch (randomimages) {

    case 0:
        imageview.image = [UIImage imageNamed:@"IMAGE_001.png"];
        break;
    case 1:
        imageview.image = [UIImage imageNamed:@"IMAGE_002.png"];
        break;
    case 2:
        imageview.image = [UIImage imageNamed:@"IMAGE_003.png"];
        break;
    case 3:
        imageview.image = [UIImage imageNamed:@"IMAGE_004.png"];
        break;
    case 4:
        imageview.image = [UIImage imageNamed:@"IMAGE_005.png"];
        break;

default:

        break;

}

如果图像按以下顺序出现：1,4,2,5,4,3 我如何确保在显示所有 5 张图像之前不会再次出现“4”？

谢谢你的帮助！

Answer 1

将图像名称存储在 NSMutableArray 中并打乱数组，例如通过类似 这样的方法 SO answer

然后循环遍历数组。

Answer 2

Create a NSMutableArray and put 0, 1, 2, 3, 4 on it then whenever a random number is selected remove it like this:

[myNSMutableArray removeObjectAtIndex:myRandNumber];


To fill the gap, all elements beyond index are moved by subtracting 1 from their index.

然后只需通过执行以下操作选择一个新的随机数：

int randomimages = rand() % 4; //4 would of course be a int var that you substract everytime a new random is generated.

等等。