1

我正在构建一个基本的 MVC 应用程序，并且我已经正确使用了所有配置文件。但应用程序仍然没有统计。这些是以下配置文件，

网页.xml,

<?xml version="1.0" encoding="UTF-8"?>

<web-app>
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>


    <servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
    </servlet-mapping>

    <welcome-file-list>
            <welcome-file>jsp/index.jsp</welcome-file>
    </welcome-file-list>

</web-app>

上下文配置

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.com/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
                           http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
                           http://www.springframework.org/schema/context
                           http://www.springframework.org/schema/context/spring-context-3.2.xsd">

    <context:annotation-config />
    <context:component-scan base-package="controllers">
    </context:component-scan>


    <bean id="viewResolver"
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="viewClass"
            value="org.springframework.web.servlet.view.JstlView" />
        <property name="prefix" value="/jsp/" />
        <property name="suffix" value=".jsp" />
    </bean>

</beans>

但我得到的错误是

org.apache.catalina.LifecycleException: org.apache.catalina.LifecycleException: org.xml.sax.SAXParseException: cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'context:annotation-config'.

我使用 glassfish 作为我的容器。

4

3 回答 3

2

您从哪里获得这些架构版本。

改变

<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.com/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
                           http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
                           http://www.springframework.org/schema/context
                           http://www.springframework.org/schema/context/spring-context-3.2.xsd">

到

<beans xmlns="http://www.springframework.org/schema/beans" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.com/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
                       http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
                       http://www.springframework.org/schema/context
                       http://www.springframework.org/schema/context/spring-context-3.1.xsd">
于 2012-07-17T10:19:33.090 回答
2

我不相信它就是xmlns:context="http://www.springframework.com/schema/context"这样xmlns:context="http://www.springframework.org/schema/context"。

组织，而不是 COM。

我希望这有帮助！:)

于 2012-11-13T09:54:40.390 回答
0

将您的架构更改为此

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
 xmlns:context="http://www.springframework.org/schema/context"
 xsi:schemaLocation="http://www.springframework.org/schema/beans
     http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
     http://www.springframework.org/schema/context
     http://www.springframework.org/schema/context/spring-context-3.0.xsd">

<context:annotation-config />
<context:component-scan base-package="controllers">
</context:component-scan>


<bean id="viewResolver"
    class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="viewClass"
        value="org.springframework.web.servlet.view.JstlView" />
    <property name="prefix" value="/jsp/" />
    <property name="suffix" value=".jsp" />
</bean>

</beans>
于 2012-07-17T17:49:07.823 回答