java - JTree：如何获取选定节点的路径

Question

有没有办法像使用类似的东西来获取 JTree 中选定节点的选定路径

String pathForNode = JTree.getLastSelectedPathComponent().getPath().toString();

Answer 1

 tree.addTreeSelectionListener(new TreeSelectionListener() {  
    public void valueChanged(TreeSelectionEvent e) {  
       TreePath tp = e.getNewLeadSelectionPath();  
       if (tp != null) {
          pathForNode = tp.getLastPathComponent();  
       }
    }  
 });

http://www.coderanch.com/t/453540/GUI/java/Getting-path-file-selected-JTree

编辑：

尝试

  tree.addMouseListener(new MouseAdapter() {
      public void mouseClicked(MouseEvent me) {
        doMouseClicked(me);
      }
    });
  }

  void doMouseClicked(MouseEvent me) {
    TreePath tp = tree.getPathForLocation(me.getX(), me.getY());
    if (tp != null) {
      System.out.println(tp.toString());
    }
  }

JTree路径

Answer 2

     tree.addTreeSelectionListener(new TreeSelectionListener() {
        public void valueChanged(TreeSelectionEvent e) {
            TreePath treepath = e.getPath();
            System.out.println("Java: " + treepath.getLastPathComponent());
            Object elements[] = treepath.getPath();
               for (int i = 0, n = elements.length; i < n; i++) {
                   System.out.print("->" + elements[i]);

         // JOptionPane.showMessageDialog(null,"->"+elements[i]);
         //lblNewLabel.setText(">"+ elements[i]);



           value+=elements[i]+"\\";


        }



        //String x=String.valueOf(value);            
        //lblNewLabel.setText(String.valueOf(value));

        JOptionPane.showMessageDialog(null, value);


        //System.out.println(value);
        }
    });

  static String value="";    //add this just before the void main function

在 C# .net 中，它曾经很容易获得路径并且对我来说有点直观。

Answer 3

我用这个：

    jTreeVarSelectedPath = "";
    Object[] paths = jTreeDirectorios.getSelectionPath().getPath();
    for (int i=0; i<paths.length; i++) {
        jTreeVarSelectedPath += paths[i];
        if (i+1 <paths.length ) {
            jTreeVarSelectedPath += File.separator;
        }
    }