我有一个动态表,我想在替代行上赋予颜色。我怎样才能用css实现这一点?我需要代码才能在 IE7+ 中工作
问问题
5363 次
4 回答
3
研究在 CSS3 中使用偶数/奇数规则。
参考:https ://developer.mozilla.org/en/CSS/:nth-child
例如,
tr:nth-child(odd)
将代表每个2n + 1
孩子的 CSS,而tr:nth-child(even)
将代表每个2n
孩子的 CSS。
于 2012-07-16T14:36:29.180 回答
2
CSS3 nth-child 选择器:
tr:nth-child(odd) {
background: red /* or whatever */;
}
于 2012-07-16T14:36:49.107 回答
2
星期五我遇到了同样的问题,我使用了 jquery 解决方案
$("tr:even").css("background-color", "#CCC");
$("tr:odd").css("background-color", "#FFF");
- 此处发布的堆栈溢出解决方案 .js 检测 DOM 中的更改
所以基本上你在头部添加 .js 脚本并触发 dom 更改的 jquery 规则。
我完成的 .js 看起来像这样
<script type="text/javascript">
(function (window) {
var last = +new Date();
var delay = 100; // default delay
// Manage event queue
var stack = [];
function callback() {
var now = +new Date();
if (now - last > delay) {
for (var i = 0; i < stack.length; i++) {
stack[i]();
}
last = now;
}
}
// Public interface
var onDomChange = function (fn, newdelay) {
if (newdelay)
delay = newdelay;
stack.push(fn);
};
// Naive approach for compatibility
function naive() {
var last = document.getElementsByTagName('*');
var lastlen = last.length;
var timer = setTimeout(function check() {
// get current state of the document
var current = document.getElementsByTagName('*');
var len = current.length;
// if the length is different
// it's fairly obvious
if (len != lastlen) {
// just make sure the loop finishes early
last = [];
}
// go check every element in order
for (var i = 0; i < len; i++) {
if (current[i] !== last[i]) {
callback();
last = current;
lastlen = len;
break;
}
}
// over, and over, and over again
setTimeout(check, delay);
}, delay);
}
//
// Check for mutation events support
//
var support = {};
var el = document.documentElement;
var remain = 3;
// callback for the tests
function decide() {
if (support.DOMNodeInserted) {
window.addEventListener("DOMContentLoaded", function () {
if (support.DOMSubtreeModified) { // for FF 3+, Chrome
el.addEventListener('DOMSubtreeModified', callback, false);
} else { // for FF 2, Safari, Opera 9.6+
el.addEventListener('DOMNodeInserted', callback, false);
el.addEventListener('DOMNodeRemoved', callback, false);
}
}, false);
} else if (document.onpropertychange) { // for IE 5.5+
document.onpropertychange = callback;
} else { // fallback
naive();
}
}
// checks a particular event
function test(event) {
el.addEventListener(event, function fn() {
support[event] = true;
el.removeEventListener(event, fn, false);
if (--remain === 0) decide();
}, false);
}
// attach test events
if (window.addEventListener) {
test('DOMSubtreeModified');
test('DOMNodeInserted');
test('DOMNodeRemoved');
} else {
decide();
}
// do the dummy test
var dummy = document.createElement("div");
el.appendChild(dummy);
el.removeChild(dummy);
// expose
window.onDomChange = onDomChange;
})(window);
$(document).ready(function () {
$("tr:even").css("background-color", "#CCC");
$("tr:odd").css("background-color", "#FFF");
onDomChange(function () {
$("tr:even").css("background-color", "#CCC");
$("tr:odd").css("background-color", "#FFF");
});
});
</script>
我想提醒这个答案,这可能不是最好的解决方案,但可以满足我的需要。:-)
于 2012-07-16T15:20:26.500 回答