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我想从以下 URL 获取所有图像并使用以下 Xpath 查询，但每次查询都返回 null。

网址： 

http://www.amazon.com/gp/browse.html?ie=UTF8&marketplaceID=ATVPDKIKX0DER&me=A219HML0CVO0HP

Xpath 查询：

$products = $xpath->evaluate('//div[@class="productTitle"]//img');
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2 回答 2

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我相信您在 img 之前有太多正斜杠：

$xpath->evaluate('//div[@class="productTitle"]/img');

这应该与该链接中存在的以下 HTML 匹配：

<div id="srProductTitle_B0000CBIFG_0" class="productTitle">
    <a href="https://rads.stackoverflow.com/amzn/click/com/B0000CBIFG" rel="nofollow noreferrer">
    <img src="http://ecx.images-amazon.com/images/I/51BZs4Gf5pL._SL160_AA160_.jpg" class="" border="0" alt="Product Details"  width="160" height="160"/><br clear="all" />Weed Eater 952701594 0.065-Inch-by-200-Foot Bulk Round String Trimmer Line
    </a>
</div>
于 2012-07-16T12:51:52.197 回答
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可能这会帮助你...

$subject = file_get_contents('http://www.amazon.com/gp/browse.html?ie=UTF8&marketplaceID=ATVPDKIKX0DER&me=A219HML0CVO0HP');
$string = preg_replace('/\s\s+/', '', $subject);

preg_match_all('/<a(.*?)href="(.*?)">(.*?)<img(.*?)src="(.*?)"(.*?)class=""(.*?)border="0"(.*?)alt="Product(.*?)Details/', $subject, $result, PREG_PATTERN_ORDER);

for ($i = 0; $i < count($result[0]); $i++) {
    echo "<pre>";
    echo $result[5][$i];
}

谢谢.....p2c

于 2012-07-23T11:32:00.330 回答