2

此插件在页面加载时读取blueimproot/server/php/files上的图像文件。我需要从数据库中读取记录，并用我的自定义结构替换“下载”HTML 结构。我想显示目录产品，通过此插件上传/删除图像会影响哪些项目。

到目前为止，我已经这样做了：

  • 我更改public function get() { ... }了blueimproot/server/php/upload.class.php以从数据库中检索记录。此函数返回 json 对象。

    public function get() {
    /* default code of Blueimp
    $file_name = isset($_REQUEST['file']) ?
    basename(stripslashes($_REQUEST['file'])) : null;
    if ($file_name) {
        $info = $this->get_file_object($file_name);
    } else {
        $info = $this->get_file_objects();
    }

    header('Content-type: application/json');
    echo json_encode($info);
    */

    include_once('../../../../connection.php');

    $id_cat = $_REQUEST['catid'];
    $query = "SELECT id, name, price, img_path FROM products WHERE id_cat = $id_cat ORDER BY id";
    $prods = mysql_query($query);

    $prod_arr = array();
    while($prod = mysql_fetch_assoc($prods)) {
        $prod_arr[] = $prod;
    }

    header('Content-type: application/json');
    echo json_encode($info);
    }

  • 我发现该函数是从blueimproot/server/php中的index.php调用的：

    switch ($_SERVER['REQUEST_METHOD']) {
    ...
    case 'GET':
        $upload_handler->get();
        break;
    ...

    }

我不知道返回的 json 对象在哪里处理以显示给 UI。已经 2 天了，仍然无法跟踪该功能流程。请帮忙。谢谢。

原始在线演示： http ://blueimp.github.com/jQuery-File-Upload/

原始插件下载： https ://github.com/blueimp/jQuery-File-Upload/downloads

4

3 回答 3

3

我的建议是在 Firebug 中打开Network 选项卡并观察任何 GET 请求server/php/index.php。如果它发生在特定事件之后，那么您将更好地了解应该查看的位置。

我确实查看了源文件，发现唯一的 GET 请求在main.js

$('#fileupload').each(function () {
  var that = this;
  $.getJSON(this.action, function (result) {
    if (result && result.length) {
      $(that).fileupload('option', 'done')
        .call(that, null, {result: result});
        }
    });
  });
}
于 2012-07-23T21:54:23.290 回答
2 
 public function get() {
    /*
    $file_name = isset($_REQUEST['file']) ?
        basename(stripslashes($_REQUEST['file'])) : null;
    if ($file_name) {
        $info = $this->get_file_object($file_name);
    } else {
        $info = $this->get_file_objects();
    }
    header('Content-type: application/json');
    echo json_encode($info);
    */
        $id_cat = $_REQUEST['catid'];
        $query = "SELECT id, name, price, img_path FROM products WHERE id_cat = $id_cat ORDER BY id";
        $prods = mysql_query($query);

        $prod_arr = array();
        while($prod = mysql_fetch_assoc($prods)) {
            //$prod_arr[] = $prod;

            $file = new stdClass();
            $file->name = "";// here image name goes i do not find image name in your select query
            $file->size = filesize($prod["img_path"]);// should be complete path
            $file->url =  $prod["img_path"];// should be relative path (http://localhost/images/234.jpg)
            $file->thumbnail_url = $prod["img_path"]; // thumbnail path
            $this->delete_type = "DELETE";
            $this->delete_url = ""; //here delete url you can delete image from database 
            array_push($prod_arr,$file);
        }
        header('Content-type: application/json');
    echo json_encode($prod_arr);
}
于 2012-07-28T18:20:35.257 回答
2

按照这个 WIKI： https ://github.com/blueimp/jQuery-File-Upload/wiki/Working-with-databases

我设置要插入数据库的上传，然后我更改了我的 GET 函数，如下所示：

            public function get() {
                $uploads = $this->query_db();
                header('Content-type: application/json');
                echo json_encode($uploads);
            }

我的 query_db 函数如下：

         public function query_db() {
    $uploads_array = array();
    $select_result = $this->query("SELECT * FROM `uploads` ORDER BY `file_name`") or die(mysql_error());
    while($query_results = mysql_fetch_object($select_result))
        {   
            $file = new stdClass();
            $file->id = $query_results->id;
            $file->name = $query_results->file_name;
            $file->size = $query_results->file_size;
            $file->type = $query_results->file_type;
            $file->url = "http://files.domain.com/".$query_results->file_name;
            $file->thumbnail_url = "http://thumbnails.domain.com/".$query_results->file_name;
            $file->delete_url = "";
            $file->delete_type = "DELETE";
            array_push($uploads_array,$file);
        }
    return $uploads_array;
}
于 2012-10-03T15:31:59.010 回答