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我对Phonegap很陌生。我正在phonegap中做一个应用程序，在这里我想从特定的url获取数据。数据在xml文件中。任何人都可以通过提出一些想法来帮助我。

提前致谢...

html>
<head>
<title>Xml file read</title>

<script type="text/javascript">
function loadXMLDoc()
{
var request = new XMLHttpRequest();
request.open("GET","http://saletrack.cynere.net/test2.xml", true);
request.onreadystatechange = function() {
    if (request.readyState == 4) {
        if (request.status == 200 || request.status == 0) {
            return request.responseXML;
            // do something with my xml
        }
    }
}
request.send();
}
</script>
</head>

<body>

<script type="text/javascript">

var xmlDoc=loadXMLDoc();
var x=xmlDoc.getElementsByTagName("author");
for (i=0;i<x.length;i++)
  {
  document.write(x[i].childNodes[0].nodeValue);
  document.write("<br />");
  } 

</script>
</body>
</html>
4

1 回答 1

1

使用 AJAX：

var request = new XMLHttpRequest();
request.open("GET", "http://saletrack.cynere.net/App.xml", true);
request.onreadystatechange = function() {
    if (request.readyState == 4) {
        if (request.status == 200 || request.status == 0) {
            var myXML = request.responseXML;
            // do something with my xml
        }
    }
}
request.send();
于 2012-07-16T12:39:51.260 回答