嗨，我在这里浏览了各种帖子，但没有一个回答我的问题，我有两个问题，1. 我编写了一个脚本来使用 poplib 获取电子邮件，一切正常，直到我尝试解析电子邮件的正文摆脱标签和其中的数据，我现在放弃了，在这里寻求帮助，希望你们能引导我走向正确的方向，因为我在哪里做错了，或者我应该怎么做才能让它发挥作用。
这是解析器脚本的来源
import sys
import socket
import poplib
import email
import csv
import re
try:
host = "mail.someserver.com"
mail = poplib.POP3(host)
print mail.getwelcome()
print mail.user("username@someserver.com")
print mail.pass_("qaiaJWkvZT")
print mail.stat()
print mail.list()
print ""
emailWriter = csv.writer(open('emailMessages.csv', 'wb'), delimiter=',', quotechar='\'', quoting=csv.QUOTE_MINIMAL)
emailWriter.writerow(['Messages'])
if mail.stat()[1] > 0:
print "You have new mail."
else:
print "No new mail."
print ""
numMessages = len(mail.list()[1])
for i in range(numMessages):
for j in mail.retr(i+1)[1]:
#print j
msg = email.message_from_string(j) # new statement
print msg.get_payload(decode=True)
#emailWriter.writerow([msg.get_payload(decode=True)]) # new statement
mail.quit()
input("Press any key to continue.")
except socket.error as e:
print "Something went wrong! :(\nREASON:\n{0}:{1}".format(e.errno, e.strerror)
raise
except:
print "Something went wrong!", sys.exc_info()[0]
raise
这是上面脚本生成的输出
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.or
g/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<style type="text/css">
BODY {
}
TD {
}
TH {
}
H1 {
}
TABLE,IMG,A {
}
</style>
</head>
<body>
<p><strong>PO Number:</strong> 35164</p>
<p><strong>Ship To:</strong><br />
Joe Pasloski<br />
16 Redwood Drive<br />Yorkton, SK S3N2X7<br />
204-473-2218</p>
<table cellspacing="0" cellpadding="5" border="1" width="710" align="left">
<tr>
</tr>
<tr>
</tr>
</table>
</body>
</html>
但是，如果我将脚本更改为直接在循环内打印 j 变量，它会给我这个
Return-Path: <orders@someserver.com>
Delivered-To: username@someserver.com
Received: (qmail 7636 invoked by uid 48); 14 Jul 2012 23:29:11 -0000
Date: 14 Jul 2012 23:29:11 -0000
Message-ID: <20120714232911.7635.qmail@b.inetuhosted.net>
To: username@someserver.com
Subject: Drop Ship Order - Joe Pasloski
From: Someserver.com <orders@someserver.com>
X-Mailer: PHP/5.2.17
MIME-Version: 1.0
Content-Type: multipart/alternative;
boundary="2631183869_50020"
Reply-to: SomeServer.com <orders@someserver.com>
X-Antivirus: avast! (VPS 120714-2, 07/15/2012), Inbound message
X-Antivirus-Status: Clean
--2631183869_50020
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: 8bit
--2631183869_50020
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: 8bit
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.or
g/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<style type="text/css">
BODY {
MARGIN-TOP: 10px;
MARGIN-BOTTOM: 10px;
MARGIN-LEFT: 10px;
MARGIN-RIGHT: 10px;
FONT-SIZE: 12px;
FONT-FAMILY: arial,helvetica,sans-serif
PADDING: 0px;
}
TD {
FONT-SIZE: 12px;
FONT-FAMILY: arial,helvetica,sans-serif
COLOR: #000000;
}
TH {
FONT-SIZE: 13px;
FONT-FAMILY: arial,helvetica,sans-serif
}
H1 {
FONT-SIZE: 20px
}
TABLE,IMG,A {
BORDER: 0px;
}
</style>
</head>
<body>
<p><strong>PO Number:</strong> 35164</p>
<p><strong>Ship To:</strong><br />
Joe Pasloski<br />
16 Redwood Drive<br />Yorkton, SK S3N2X7<br />
204-473-2218</p>
<p><strong>Items:</strong>
<table cellspacing="0" cellpadding="5" border="1" width="710" align="left">
<tr>
<th align="left" width="100">SKU</th>
<th align="left" width="550">Product</th>
<th align="left" width="60">Qty</th>
</tr>
<tr>
<td>JJ-Hamper-Firetruck</td>
<td>Frankie's Fire Truck Laundry Hamper</td>
<td>1</td>
</tr>
</table>
</body>
</html>
如果我需要处理原始消息，我怎样才能有效地让消息的正文部分去除不必要的 html 标签而不丢失任何数据？或者，如果可以通过使用 get_payload() 方法，我该怎么做才能使其工作。
请帮忙！
2. 还有没有办法使用正则表达式获取表中包含的所有 SKU 信息？如果你也能提供给我，那将是一个加号。万分感谢