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我正在构建一个从订阅表中获取用户的函数。然后这些用户用于获取他们的个人文章并以有序的方式显示它们。

我已经成功做到了一半。它将获取用户，然后输出用户的文章。但是一次需要一个用户。我正在寻找一种方法来选择订阅表中的所有用户并将它们全部获取，以便我可以同时显示它们，但按日期排序。

表格：

**Subscribe :** 
Lastviewed ( datetime ) 
Uniqueuser ( userid )
Subscription ( subscribed users id)

**Article:**
date_posted ( datetime )
uniqueuser ( users id)

这就是我得到的：

$sesname = $_SESSION['full_name'];
$sesid = $_SESSION['user_id'];

connectDB();
$sql ="select * from subscribe where uniqueuser = '$sesid'";
$rsd = mysql_query($sql);

while ($row = mysql_fetch_array($rsd))
{
    $subscription = $row['subscription'];
    $lastviewed = $row['lastviewed'];
    $substart = $row['substart'];
    $sql3 = "select * from article 
        where uniqueuser = '$subscription' 
        and date_posted > '$lastviewed' 
        order by date_posted 
        desc limit 0, 7";

    $rsd3 = mysql_query($sql3);
    $newarticles = mysql_num_rows($rsd3);

    while ($row3 = mysql_fetch_assoc($rsd3)) {
        $id  =$row3['id'];
        $title = $row3['title'];
        $uid = $row3['uniqueuser'];
        $sql2 = "SELECT * FROM users WHERE id = '$uid'";  
        $result2 = mysql_query($sql2);

        while ($row2 = mysql_fetch_assoc($result2)) {
            $name = $row2['user_name'];
            echo "<b><a>{$name}</a></b> wrote an <a>article</a><br>";
        }
    }
} //END SUBSCRIBE

这输出：

User A wrote an article (1th july)
User A wrote an article (2th july)
User A wrote an article (3th july)
User A wrote an article (4th july)
User B wrote an article (1th july)
User B wrote an article (2th july)
User B wrote an article (3th july)
User B wrote an article (4th july)

即使用户 B 的文章在用户 A 的帖子之间发布，它也会一个接一个地订购它。

想要的输出：

User A wrote an article (1th july)
User B wrote an article (1th july)
User A wrote an article (2th july)
User B wrote an article (2th july)
User A wrote an article (3th july)
User B wrote an article (3th july)
User A wrote an article (4th july)
User B wrote an article (4th july)

那么，无论用户写了什么，我如何将它打包并按日期排序？我认为我的问题是由于订阅查询上的 while 循环，但我不知道有任何其他方法可以做到这一点。任何帮助是极大的赞赏！=)

4

1 回答 1

1

或多或少简单地加入所涉及的 3 个表并按a.date_posted排序

$sql2 = "select a.* , u.user_name, a.id as article_id, u.id as user_id 
    from subscribe s
    join article a on s.subscription = a.uniqueuser AND s.lastviewed < a.date_posted
    join user u on a.uniqueuser = u.id
    where s.uniqueuser = '$sesid'
    order by a.date_posted 
    desc limit 0, 7";

$result2 = mysql_query($sql2);

while ($row2 = mysql_fetch_assoc($result2)) {
    $name = $row2['user_name'];
    $date = $row2['date_posted'];
// fetch the columns having the same name using aliases
$a_id = $row2['article_id'];
$u_id = $row2['user_id'];

    echo "<b><a>{$name}</a></b> wrote an <a>article</a>({$date})<br>";
}

编辑

修复条件 s.lastviewed < a.date_posted

添加关于加入

两个或多个表之间的连接是具有有效/真实条件（ON 和 WHERE）的表的所有元素的所有组合的集合

于 2012-07-14T12:34:34.133 回答