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我正在使用以下数据库构建一个包含地理数据的数据库：PostgreSQL 9.1、Django 1.3.1、psycopg2 2.4.5 并使用库 GEOS 3.3.0、PostGIS 1.5.4 和 ProJ 4.7.0。

我有一个命令将形状文件加载到数据库中，并进行了一些优化以使形状更简单。

为了保持模型简单，我将只放置有问题的字段：

class Circonscription(models.Model):
    shape = models.GeometryField()
    simple_shape = models.GeometryField()
    centroid = models.PointField(null=True)

当我想从形状文件创建一个时，我这样做：

Circonscription.objects.create(
            id_cep=feature['id_cep'],
            co_cep=feature['co_cep'],
            nm_cep=feature['nm_cep'],
            nmtri_cep=feature['nmtri_cep'],
            dh_maj=feature['dh_maj'],
            shape=geometry.wkt,
            simple_shape=simple_geometry.wkt,
            centroid=geometry.geos.centroid)

现在当我运行我的命令时，它失败并出现以下错误：

File "/home/pg/Projets/python/myproject/circonscriptions/management/commands/loadshapefiles.py", line 174, in add_boundaries_for_layer
centroid=geometry.geos.centroid)
File "/home/pg/.virtualenvs/myproject/local/lib/python2.7/site-packages/django/db/models/manager.py", line 138, in create
    return self.get_query_set().create(**kwargs)
  File "/home/pg/.virtualenvs/myproject/local/lib/python2.7/site-packages/django/db/models/query.py", line 360, in create
    obj.save(force_insert=True, using=self.db)
  File "/home/pg/.virtualenvs/myproject/local/lib/python2.7/site-packages/django/db/models/base.py", line 460, in save
    self.save_base(using=using, force_insert=force_insert, force_update=force_update)
  File "/home/pg/.virtualenvs/myproject/local/lib/python2.7/site-packages/django/db/models/base.py", line 543, in save_base
    for f in meta.local_fields if not isinstance(f, AutoField)]
  File "/home/pg/.virtualenvs/myproject/local/lib/python2.7/site-packages/django/db/models/fields/subclassing.py", line 28, in inner
    return func(*args, **kwargs)
  File "/home/pg/.virtualenvs/myproject/local/lib/python2.7/site-packages/django/db/models/fields/__init__.py", line 786, in get_db_prep_save
    return connection.ops.value_to_db_decimal(self.to_python(value),
  File "/home/pg/.virtualenvs/myproject/local/lib/python2.7/site-packages/django/db/models/fields/__init__.py", line 761, in to_python
    return decimal.Decimal(value)
  File "/usr/lib/python2.7/decimal.py", line 658, in __new__
    raise TypeError("Cannot convert %r to Decimal" % value)
TypeError: Cannot convert <django.contrib.gis.gdal.field.OFTInteger object at 0x2458b50> to Decimal

有人知道吗？

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2 回答 2

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它以某种方式与值的编码有关，然后另一个错误是关于这个问题的，最终解决了它。在将值传递给模型进行保存之前，请务必将它们转换为正确的编码 (utf-8)。

于 2012-07-17T19:24:15.110 回答
0

Decimal 需要一个字符串，但您正在为它提供一个 OTFInteger，您需要在过程中的某处将其转换为字符串

于 2012-07-14T09:52:46.787 回答