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< 想要从包含 Arraylist 的对象中创建一个 parcelable，但是在我的 readFromParcel 方法中，我收到错误类型不匹配：无法从 void 转换为 ArrayList。我该怎么做才能从我的包裹中正确读取我的 ArrayList？

编辑：在下面的答案的帮助下，我现在不再收到类型不匹配错误，但现在我收到消息“-令牌上的语法错误”>“，无效名称-令牌上的语法错误“>”，此之后的表达式令牌”

编辑清理项目时解决了新错误。

这是我的代码

public class Game implements Parcelable{

private ArrayList<Stone> allStones;

public Game(){
    allStones = new ArrayList<Stone>();
    for(int x=0; x<10; x++) {
        for(int y=0; y<10; y++) {
            if((x+y)%2 == 1 && y<4){
                Stone stone = new Stone(x, y, Stone.WHITE);
                allStones.add(stone);
            } else if((x+y)%2 == 1 && y>5){
                Stone stone = new Stone(x, y, Stone.BLACK);
                allStones.add(stone);
            }
        }
    }
}

public Game(Parcel in) {
    allStones = new ArrayList<Stone>();
    readFromParcel(in);
}

public ArrayList<Stone> getAllStones() {
    return allStones;
}

public void removeFromStones(Stone stone) {
    allStones.remove(stone);
}

public int describeContents() {
    return 0;
}

public void writeToParcel(Parcel dest, int flags) {
    dest.writeTypedList(allStones);
}

private void readFromParcel(Parcel in) {
    in.readTypedList(allStones, Stone.CREATOR); //This line has the error in it
}
}

和石头类

public class Stone implements Parcelable{
private int x, y, color;
private Boolean king;

public static final int BLACK = 0;
public static final int WHITE = 1;

public Stone(int x, int y, int color) {
    this.x = x;
    this.y = y;
    this.color = color;
    this.king = false;
}

public Stone(Parcel in) {
    readFromParcel(in);
}

public int getX() {
    return x;
}

public int getY() {
    return y;
}

public int getColor() {
    return color;
}

public boolean getKing() {
    return king;
}

public void setKing() {
    king = true;
}

public void setXY(int x, int y) {
    this.x = x;
    this.y = y;
}

public int describeContents() {
    return 0;
}

public void writeToParcel(Parcel dest, int flags) {
    dest.writeInt(x);
    dest.writeInt(y);
    dest.writeInt(color);
    dest.writeByte((byte) (king ? 1:0));
}

public void readFromParcel(Parcel in) {
    x = in.readInt();
    y = in.readInt();
    color = in.readInt();
    king = in.readByte() == 1;
}

public final static Creator<Stone> CREATOR = new Parcelable.Creator<Stone>() {

    public Stone createFromParcel(Parcel source) {
        return new Stone(source);
    }

    public Stone[] newArray(int size) {
        return new Stone[size];
    }
};
}
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1 回答 1

2

readTypedList()不返回值。它将对象列表放入您作为第一个参数传递的列表中。您的代码应如下所示：

private void readFromParcel(Parcel in) {
    in.readTypedList(allStones, Stone.CREATOR); // Should work now
}
于 2012-07-13T12:35:46.070 回答