0

我正在尝试将 makeList[start] 的索引输出到 makeList[end]。我有所有正确的开始和结束值，总共大约 11 对。但是，我没有得到正确的输出，因为它没有打印出所有可能的输出。为什么会这样？

def searchPFAM(fname):
   with open(fname,'rb') as f:
       root = etree.parse(f)
       for lcn in root.xpath("/protein/match[@dbname='PFAM']/lcn"):
          try:
             start = int(lcn.get("start"))
             end = int(lcn.get("end"))
             yield start, end
          except (TypeError , ValueError) as e:
             pass 

uniprotID ='Q14591'

def createRef():
    fileInput = open(uniprotID +'.txt','r')
    readAA = fileInput.read()
    store_value = (readAA.partition('\n'))
    aaSequence = store_value[2].replace('\n', '')
    makeList = list(aaSequence)
    return makeList

makeList = createRef()

for start, end in searchPFAM(fname):
    print start, end  
    if start <= end:
        with open('newfile.txt','w') as fileinput:
            while start <= end:
                result = makeList[start]
                fileinput.write(result)
                start += 1
4

2 回答 2

3

只是一个猜测，但你可能想要：

with open('newfile.txt','w') as fileinput:
    for start, end in searchPFAM(fname):
        print start, end  
        if start <= end:
            while start <= end:
                result = makeList[start]
                fileinput.write(result)
                start += 1

您的旧版本仅向文件写入 1 个开始/结束循环，将其关闭，然后打开一个新文件（与旧文件同名），写入 1 个开始/结束循环，关闭文件......换句话说，你'在每次循环迭代时重写文件。

于 2012-07-12T19:54:34.040 回答
0

最常见的原因：您需要在脚本终止之前刷新输出文件。

上面的片段：

with open('newfile.txt','w') as fileinput:
        while start <= end:
            result = makeList[start]
            fileinput.write(result)
            start += 1
fileinput.flush()
于 2012-07-12T19:47:48.937 回答