0

我如何将这两个查询组合成 1 并在大表上高效运行？

SELECT  field1, count(1) as requestCount
FROM table1
WHERE date_complete >= '2012-06-12 00:00:00' 
      AND date_complete <= '2012-07-12 23:59:59' 
GROUP BY field1

SELECT field2, count(1) as completeCount
FROM table1
WHERE date_complete >= '2012-06-12 00:00:00' 
      AND date_complete <= '2012-07-12 23:59:59' 
GROUP BY field2

表包含涉及多个用户的进程的信息。例如，假设第一人创建请求，第二人完成请求，第三人通过提交来关闭请求。

我想计算每个用户在特定时间范围内请求、完成和归档的数量

我希望这两个结合起来看起来像

+----------------+--------------+
| field1         | requestCount |
+----------------+--------------+
| PJB            |            1 |
| RFD            |            6 |
| YAS            |            4 |
+----------------+--------------+

+

+---------+---------------+
| field2  | completeCount |
+---------+---------------+
| PJB     |            4  |
| YAS     |            5  |
+---------+---------------+

=

+----------------+--------------+---------------+
| Username       | requestCount | completeCount |
+----------------+--------------+---------------+
| PJB            |            1 |             4 |
| RFD            |            6 |             0 |
| YAS            |            4 |             5 |
+----------------+--------------+---------------+
4

4 回答 4

1

只是在这里猜测，但我认为您需要：

SELECT
    u .Username
  , t1.requestCount
  , t2.completeCount
FROM
        ( SELECT field1 AS Username
          FROM table1
          UNION
          SELECT field2
          FROM table2
        ) AS u
    LEFT JOIN
        ( SELECT field1
               , COUNT(*) AS requestCount
          FROM table1
          WHERE date_complete >= '2012-06-12' 
            AND date_complete < '2012-07-13' 
          GROUP BY field1
        ) AS t1  
            ON t1.field1 = u.Username
    LEFT JOIN
        ( SELECT field2
               , COUNT(*) AS completeCount
          FROM table1
          WHERE date_complete >= '2012-06-12' 
            AND date_complete < '2012-07-13' 
          GROUP BY field2 
        ) AS t2
            ON t2.field2 = u.Username   
;

如果您有一个user表，只需将第一个派生表替换为user AS u

于 2012-07-12T15:56:51.653 回答
1 
select  o.USERNAME, a.requestCount , b.completeCount from (SELECT  USERNAME
FROM owner_login_pass )
 as o left join (SELECT field1, count(1) as requestCount
FROM table1
WHERE date_complete between '2012-06-12 00:00:00' and '2012-07-12 23:59:59' 
GROUP BY field1) as a on o.USERNAME=a.field1
left join (SELECT field2, count(1) as completeCount
FROM table1
WHERE date_complete between '2012-06-12 00:00:00' and '2012-07-12 23:59:59' 
GROUP BY field2) as b on o.USERNAME=b.field2

您需要确保 field1 拥有您需要为其显示数据的所有用户。否则，您还需要加入用户表。

于 2012-07-12T16:04:04.247 回答
0

我不认为你可以将它们结合起来（除了 with UNION），但你可以通过使用来稍微改进它：WHERE date_complete BETWEEN '2012-06-12 00:00:00' AND '2012-07-12 23:59:59'

于 2012-07-12T15:29:42.757 回答
0

你需要 ：：：

Select * from 
(
   SELECT  field1, count(1) as requestCount
FROM table1
WHERE date_complete between '2012-06-12 00:00:00' and '2012-07-12 23:59:59'  
GROUP BY field1 ) tab1
left join
(
SELECT fied2, count(1) as completeCount
FROM table1
WHERE date_complete between '2012-06-12 00:00:00' and '2012-07-12 23:59:59' 
GROUP BY field2) tab2 on (tab1.field1 = tab2.field2)
于 2012-07-12T15:30:10.290 回答