0

没有Spring bean注入的经验。

<beans:bean id="ModeService"
        class="<path>Service">
    <beans:property name="Mode" value="true"/>
</beans:bean>

<beans:bean id="Filter"
       class="<path>.RequestFilter">
    <custom-filter position="FIRST" />
</beans:bean>

如何将 ModeService bean 注入到 Filter bean 中?

好的,我在春天注射了@William 所以有:

<beans:bean id="maintenanceModeService"
        class="<path>.MaintenanceService">
    <beans:property name="maintenanceMode" value="true"/>
</beans:bean>

<beans:bean id="maintenanceFilter"
       class="<path>.MaintenanceRequestFilter">
    <custom-filter position="FIRST" />
    <beans:property name="modeService" ref="maintenanceModeService"/>
</beans:bean>

在 MaintenanceService 中,我添加了 setter/getter 来调用变量:

boolean maintenanceMode;

public void setMaintenanceMode(boolean mode)
{
    this.maintenanceMode = mode;
}

public boolean getMaintenanceMode()
{
    return maintenanceMode;
}

并将 setter/getter 附加到 MaintenanceRequestFilter:

boolean modeService;

public void setModeService(MaintenanceService maintenanceMode)
{
    this.modeService = maintenanceMode;
}

public MaintenanceService getMaintenanceMode()
{
    return modeService;
}

然后在 doFilter() 中调用 modeService

但是……错了……

4

2 回答 2

0

You can use ref attribute to define reference to another bean. Filter class should have property of type ModeService so that you can define it in <property> tag using ref attribute.

<beans:bean id="Filter" class="<path>.RequestFilter">
    <custom-filter position="FIRST" />
    <beans:property name="modeService" ref="ModeService"/>
</beans:bean>
于 2012-07-12T08:49:32.940 回答
0
<beans:bean id="Filter" class="<path>.RequestFilter">
    <custom-filter position="FIRST" />
    <beans:property name="modeService" ref="ModService"/>
</beans:bean>

你应该在你的类中有一个 getter/setter 方法

class RequestFilter{
    public void setModeService(ModService modService){
        // some set code here
    }

    public ModeService getModeService(){
        // some set code here
        return modService;
    }
}
于 2012-07-12T08:57:21.400 回答