7

我的数据库中有一个时间字段,它的值为 22:05

我想减去 5 分钟。当该字段为 datetime 时,我使用 sub_date 并且工作正常,但我无法使用 time 字段获取它,我收到一个我不知道如何处理的警告;

mysql>  SELECT scheduleFinalTime FROM clientSchedule WHERE clientScheduleID = 3;
+-------------------+
| scheduleFinalTime |
+-------------------+
| 22:05:00          |
+-------------------+
1 row in set (0.00 sec)

mysql> SELECT date_sub(scheduleFinalTime, INTERVAL 5 MINUTE) FROM clientSchedule WHERE clientScheduleID = 3;
+------------------------------------------------+
| date_sub(scheduleFinalTime, INTERVAL 5 MINUTE) |
+------------------------------------------------+
| NULL                                           |
+------------------------------------------------+
1 row in set, 1 warning (0.00 sec)

mysql> show warnings;
+---------+------+------------------------------------------------------------+
| Level   | Code | Message                                                    |
+---------+------+------------------------------------------------------------+
| Warning | 1264 | Out of range value for column 'scheduleFinalTime' at row 1 |
+---------+------+------------------------------------------------------------+
 1 row in set (0.00 sec)

先感谢您

4

2 回答 2

9

Mysql 对此有一个SUBTIME()函数。

SUBTIME(expr1,expr2)

SUBTIME() returns expr1 − expr2 expressed as a value in the same format as expr1. expr1 is a time or datetime expression, and expr2 is a time expression.

mysql> SELECT SUBTIME('2007-12-31 23:59:59.999999','1 1:1:1.000002');
        -> '2007-12-30 22:58:58.999997'
mysql> SELECT SUBTIME('01:00:00.999999', '02:00:00.999998');
        -> '-00:59:59.999999'
于 2012-07-12T08:28:14.540 回答
2

对于那些使用 mysql 4.x

SEC_TO_TIME(TIME_TO_SEC(t2) - TIME_TO_SEC(t1))
于 2015-11-17T18:19:18.630 回答