-1

在课堂a which extends MainScreen上,我也想调用bclass which extends MainScreen

当我传入b.this显示的函数错误时No enclosing instance of the type b is accessible in

4

2 回答 2

0

嗨,这很简单,我会告诉你简单的方法

假设你有两个班级

1)屏幕1

2)屏幕2

screen1.java

public class screen1 extends MainScreen
{
   // some lines of code 
   //this is method to going to next screen in side that method 
   UiApplication.getUiApplication().pushScreen(new screen2(screen1.this));
}

screen2.java

public class screen2 extends MainScreen
{
   private Screen1 screen1Object;
   // here take constructer
   public screen2(Screen1 screen1Object)
   {
      this.screen1Object=screen1Object;
   }
}

在这里你可以使用那个 screen1Object

于 2012-07-12T08:06:56.470 回答
0

您可以使用此代码

UiApplication.getUiApplication().invokeAndWait(new Runnable() 
{   
    public void run() 
    {
        UiApplication.getUiApplication().pushScreen(new NewScreen());
    }
});
于 2012-07-12T11:09:19.103 回答