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我正在尝试向我的应用程序添加推送通知功能,但我遇到了奇怪的问题。

在我的第一次尝试中,我得到了设备的 regId;但在该设备试图从 GCM 中自行注销之后;实际上它成功了,因为我失去了 regId 但不是我无法再次获得它。

在 LogCat 我看到这些行。

07-12 08:40:25.615: V/GCMRegistrar(10648): Registering receiver
07-12 08:40:25.620: D/GCMRegistrar(10648): resetting backoff for PACKAGENAME
07-12 08:40:25.635: V/GCMRegistrar(10648): Unregistering app PACKAGENAME
07-12 08:40:28.570: D/GCMRegistrar(10648): resetting backoff for PACKAGENAME
07-12 08:40:28.570: V/GCMRegistrar(10648): Unregistering app PACKAGENAME
07-12 08:40:29.125: D/GCMRegistrar(10648): resetting backoff for PACKAGENAME
07-12 08:40:29.130: V/GCMRegistrar(10648): Unregistering app PACKAGENAME
07-12 08:40:39.655: D/GCMRegistrar(10648): resetting backoff for PACKAGENAME
07-12 08:40:39.660: V/GCMRegistrar(10648): Unregistering app PACKAGENAME
07-12 08:40:40.605: D/GCMRegistrar(10648): resetting backoff for PACKAGENAME
07-12 08:40:40.605: V/GCMRegistrar(10648): Unregistering app PACKAGENAME
07-12 08:40:41.350: D/GCMRegistrar(10648): resetting backoff for PACKAGENAME
07-12 08:40:41.350: V/GCMRegistrar(10648): Unregistering app PACKAGENAME
07-12 08:40:43.255: D/GCMRegistrar(10648): resetting backoff for PACKAGENAME
07-12 08:40:43.255: V/GCMRegistrar(10648): Unregistering app PACKAGENAME

我试图在我的应用程序中实现 GCM Demo Application 的代码,所以这里是代码。

GCMRegistrar.checkDevice(this);
GCMRegistrar.checkManifest(this);

registerReceiver(mHandleMessageReceiver, new IntentFilter(DISPLAY_MESSAGE_ACTION));
final String regId = GCMRegistrar.getRegistrationId(this);

if (regId.equals("")) {
    // Automatically registers application on
    // startup.
    GCMRegistrar.register(this, SENDER_ID);
} else {
    Log.v(TAG, "Already registered");
    // Device is already registered on GCM, needs to
    // check if it is
    // registered on our server as well.
    if (!GCMRegistrar.isRegisteredOnServer(this)) {
        // Try to register again, but not in the UI
        // thread.
        // It's also necessary to cancel the thread
        // onDestroy(),
        // hence the use of AsyncTask instead of a
        // raw thread.
        final Context context = this;
        mRegisterTask = new AsyncTask<Void, Void, Void>() {
            mRegisterTask.execute(null, null, null);
        }
    }
}
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1 回答 1

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我发现了我的问题,都是我的错和愚蠢。

我被添加GCMRegistrar.unregister ()到评估中;因此调试的每一步都会导致重新评估此代码并调用注销。

我不想删除它,可能有像我这样的人;)

于 2012-07-12T07:04:26.767 回答