4

我需要用 C# 编写一个基于 Windows 的服务来监听 WebSphere MQ 中配置的请求队列。我成功地将请求放入 MQ 并获得了相关 ID,但作为响应,我没有得到实际结果。

我想开发一个系统,每当有新消息到达队列时,服务应该接收消息并处理请求。我可以使用我的相关 ID 映射该响应。

4

2 回答 2

6

下面的代码解决了我的问题。

class Program
{
    static void Main(string[] args)
    {
        Program app = new Program();
        app.Setup();
        Console.ReadLine();

    }

    public void Setup()
    {
        XMSFactoryFactory xff = XMSFactoryFactory.GetInstance(XMSC.CT_WMQ);
        IConnectionFactory cf = xff.CreateConnectionFactory();
        cf.SetStringProperty(XMSC.WMQ_HOST_NAME, "10.87.188.156(7111)");
        cf.SetIntProperty(XMSC.WMQ_PORT, 7111);
        cf.SetStringProperty(XMSC.WMQ_CHANNEL, "QMEIGS1.CRM.SVRCONN");
        cf.SetIntProperty(XMSC.WMQ_CONNECTION_MODE, XMSC.WMQ_CM_CLIENT);
        cf.SetStringProperty(XMSC.WMQ_QUEUE_MANAGER, "QMEIGS1");
        cf.SetIntProperty(XMSC.WMQ_BROKER_VERSION, XMSC.WMQ_BROKER_V1);

        IConnection conn = cf.CreateConnection();
        Console.WriteLine("connection created");
        ISession sess = conn.CreateSession(false, AcknowledgeMode.AutoAcknowledge);
        IDestination dest = sess.CreateQueue("DOX.APYMT.ESB.SSK.RPO.02");
        IMessageConsumer consumer = sess.CreateConsumer(dest);
        MessageListener ml = new MessageListener(OnMessage);
        consumer.MessageListener = ml;
        conn.Start();
        Console.WriteLine("Consumer started");


    }

    private void OnMessage(IMessage msg)
    {
        ITextMessage textMsg = (ITextMessage)msg;
        Console.Write("Got a message: ");
        Console.WriteLine(textMsg.Text);
    }

}
于 2013-03-11T12:12:03.597 回答
1

我正在连接到 Z/OS 大型机上的 MQ。Rashmi 的代码示例对我有用,但我需要更改“OnMessage”方法,如下所示来提取消息:

    private void OnMessage(IMessage msg)
    {
        IBytesMessage bytesMessage = (IBytesMessage)msg;

        var buffer = new byte[bytesMessage.BodyLength];
        bytesMessage.ReadBytes(buffer, (int)bytesMessage.BodyLength);
        var messageAsText = Encoding.Unicode.GetString(buffer);

        Console.Write("Got a message: ");
        Console.WriteLine(messageAsText);
    }
于 2015-12-28T09:45:52.273 回答