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我编写了一个脚本来获取用户的浏览器版本，但我需要清理输出。该脚本的作用是查看 @ 和 IE8 的 apache 日志，然后通过电子邮件将信息发送给我。我遇到的问题是输出，因为当 grep 找到电子邮件地址和 IE8 时，它给了我完整的输出 - 即 /page/code/user@foobar.com/home.php 而我正在寻找的输出只是电子邮件地址，并且每天只记录一次此信息：

例子：

用户@foobar IE8

谢谢

#!/bin/bash

#Setting date and time (x and y and z aren't being used at the moment)
x="$(date +'%d/%b/%Y')"
y="$(date +'%T')"
z="$(date +'%T' | awk 'BEGIN { FS =":"} ; {print $1}')"

#Human readable for email title
emaildate=$(date +"%d%b%Y--Hour--%H")

#Setting date and time for grep and filename
beta="$(date +'%d/%b/%Y:%H')"
sigma="$(date +'%d-%b-%Y-%H')"

#CurrentAccess logs
log='/var/logs/access.log'

#Set saved log location
newlogs=/home/user/Scripts/browser/logs

#Prefrom the grep for the current day
grep @ $log | grep $beta | awk 'BEGIN { FS = " " } ; { print $7 }' | sort -u >> $newlogs/broswerusage"$sigma".txt 
mail -s "IE8 usage for $emaildate" user@exmaple.com < $newlogs/broswernusage"$sigma".txt
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