我有一个对特定 URL 执行 GET 的 java servlet 类。我还将数据作为 GET 的一部分传递。
我需要的是在接收此数据的 HTTP 服务器代码中,如何将基于用户的响应数据插入到 Header 中,以便我的调用 Java servlet 类可以读取它。
我可以读取标准响应内容,例如 .getResponseCode() 等,但我需要以某种方式将自己的响应插入到标题中。如何才能做到这一点?我该如何阅读?
这是我的 java servlet 发送类:
public void sendRequest(String data, String sendUrl) throws Throwable{
String messageEncoded = URLEncoder.encode(data, "UTF-8");
String message = URLDecoder.decode(messageEncoded);
System.out.println("messageEncoded : " + messageEncoded);
System.out.println("messageDecoded : " + message);
try {
URL url = new URL(sendUrl);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setRequestMethod("GET");
OutputStreamWriter writer = new OutputStreamWriter(connection.getOutputStream());
writer.write(message);
writer.close();
BufferedReader rd = null;
StringBuilder sb = null;
String line = null;
System.out.println(" *** headers ***");
for (Entry<String, List<String>> headernew : connection.getHeaderFields().entrySet()) {
System.out.println(headernew.getKey() + "=" + headernew.getValue());
}
System.out.println(" \n\n*** Body ***");
rd = new BufferedReader(new InputStreamReader(connection.getInputStream()));
sb = new StringBuilder();
while ((line = rd.readLine()) != null) {
sb.append(line + '\n');
}
System.out.println("body=" + sb.toString());
System.out.println("connection.getResponseCode() : " + connection.getResponseCode());
System.out.println("connection.getResponseMessage()" + connection.getResponseMessage());
if (connection.getResponseCode() == HttpURLConnection.HTTP_OK) {
// Ok
} else {
// Server returned HTTP error code.
}
} catch (MalformedURLException e) {
// ...
System.out.println(this.getClass() + " : MalformedURLException Error occured due to: " + e);
} catch (IOException e) {
System.out.println(this.getClass() + " : IOException Error occured due to: " + e);
}
}