2

我正在尝试使用 for 语句（输入字符 1、输入字符 2 等）获取用户对 sortValues[] 数组的输入。

但是，当我执行此操作时，程序将不允许我输入字符 2，而是直接跳到字符 3，如下所示。

在此处输入图像描述

如何解决这个问题？代码包含在下面。

谢谢！

static public void s_1d_char () {
            int counter=0;
            int x=0;
            c.print("How many characters? ");
            counter = readInt();

            char[] sortValues = new char[counter+1];

            for (x=1;x<=counter;x++) {
                    System.out.println("Enter character "+(x)+":");
                sortValues[x] = readChar();
            }
    }

readChar 实现（来自库）：

public synchronized char readChar ()
{
char result, ch;

if (ungotChar != EMPTY_BUFFER)
{
    result = (char) ungotChar;
    ungotChar = EMPTY_BUFFER;
    return (result);
}

if (lineBufferHead != lineBufferTail)
{
    result = lineBuffer [lineBufferTail];
    lineBufferTail = (lineBufferTail + 1) % lineBuffer.length;
    return (result);
}

startRow = currentRow;
startCol = currentCol;
if (currentRow > maxRow)
{
    startRow++;
    currentCol = 1;
}

// Turn cursor on if necessary
consoleCanvas.setCursorVisible (true);

// Wait for a character to be entered
while (true)
{
    ch = getChar ();

    if (ch == '\n')
    {
    clearToEOL = false;
    if (echoOn)
        print ("\n");
    clearToEOL = true;
    lineBuffer [lineBufferHead] = '\n';
    lineBufferHead = (lineBufferHead + 1) % lineBuffer.length;
    break;
    }
    if (ch == '\b')
    {
    if (lineBufferHead == lineBufferTail)
    {
        consoleCanvas.invertScreen ();
    }
    else
    {
        int chToErase;

        lineBufferHead = (lineBufferHead + lineBuffer.length - 1) % lineBuffer.length;
        chToErase = lineBuffer [lineBufferHead];
        if (echoOn)
        {
        if (chToErase != '\t')
        {
            erasePreviousChar ();
        }
        else
        {
            int cnt;
            eraseLineOfInput ();
            cnt = lineBufferTail;
            while (cnt != lineBufferHead)
            {
            print (lineBuffer [cnt]);
            cnt = (cnt + 1) % lineBuffer.length;
            }
        }
        }
    }
    } // if backspace
    else if (ch == '\025')
    {
    if (echoOn)
    {
        eraseLineOfInput ();
    }
    lineBufferHead = lineBufferTail;
    }
    else
    {
    if (echoOn)
    {
        print (ch);
    }
    lineBuffer [lineBufferHead] = ch;
    lineBufferHead = (lineBufferHead + 1) % lineBuffer.length;
    }
} // while

result = lineBuffer [lineBufferTail];
lineBufferTail = (lineBufferTail + 1) % lineBuffer.length;

// Turn cursor on if necessary
consoleCanvas.setCursorVisible (false);

return (result);
}
4

2 回答 2

1

而不是readChar()尝试：

sortValues[x] = Integer.parseInt(System.console().readLine());

如何从 Java 中的标准输入中读取整数值

于 2012-07-10T21:45:50.547 回答
1

我建议使用扫描仪获取用户输入：

import java.util.Scanner;

// ...
int counter = 0;

System.out.println("How many characters?");
Scanner keyboard = new Scanner(System.in);
counter = keyboard.nextInt();

char[] sortValues = new char[counter+1];

// Start your index variable off at 0
for (int x = 0; x < counter; x++) { 
  System.out.println("Enter character "+(x)+":");
  keyboard = new Scanner(System.in);
  String line = keyboard.nextLine();
  sortValues[x] = line.charAt(0);
}

这将捕获该行的第一个字符。如果用户输入多个字符，程序将只读取第一个字符。x此外，考虑到数组是基于 0 的索引，您应该真正从 0 开始索引变量。

于 2012-07-10T22:15:14.407 回答