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我可以在 SOAP UI 中执行 POST 请求。但是我不能从 java 做同样的事情,尝试了大约 5-6 个小时,但找不到获胜的组合。这是我正在尝试制作的帖子的 xsd 架构部分:

<method name="POST">
<request>
<param name="username" style="query" type="xs:string"/>
<param name="id" style="query" type="xs:long"/>
<representation mediaType="multipart/form-data"/>
</request>

我只是在soap ui中c/p有效载荷:

<?xml version="1.0" encoding="UTF-8"?>
<ImageList xmlns="http://someurl/1.0/image" >
  <Image>
    <Name>sampler.jpg</Name>
    <Filename>C:\\sampler.jpg</Filename>
    <Label>
      <Value>Test image</Value>
    </Label>
    <ImageMetadata>
      <Format>jpg</Format>
      <Height>300</Height>
      <Width>400</Width>
    </ImageMetadata>
  </Image>
</ImageList>

然后我在附件选项卡中添加附件。Name, Content-Type, 等等,我得到了有效的响应代码,但是我没有设法对 java 做同样的事情,这就是我得到的:

HttpRequestBase post = new HttpPost();
    HttpClient client = new DefaultHttpClient();
    try {
        post.setURI(new URI(URL));
    } catch (URISyntaxException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }
    // set number of retries
    post.getParams().setParameter(HttpMethodParams.RETRY_HANDLER, new DefaultHttpMethodRetryHandler(1, false));
    HttpResponse response = null;
    HttpPost post = (HttpPost) method;
    try {
    post.setURI(new URI(URL));
    } catch (URISyntaxException e1) {
    // TODO Auto-generated catch block
    e1.printStackTrace();
    }

    FileBody uploadFilePart = new FileBody(new File("C:\\sampler.jpg"));
    MultipartEntity reqEntity = new MultipartEntity();
    reqEntity.addPart("upload-file", uploadFilePart);

    //payload
    String requestBody = fileToString("src/main/resources/imageBodyPayload.xml");

    HttpParams parameters = new BasicHttpParams();
    parameters.setLongParameter("id", 951);
    parameters.setParameter("username", "test");

    post.setParams(parameters);
    post.setEntity(new StringEntity(requestBody, "multipart/form-data", HTTP.UTF_8));
    response = client.execute(post);

所以我将有效负载设置为发布请求的字符串,但我不能同时添加文件附件。

这是来自soap ui的原始请求的样子:

POST http://localhost:9080/imageUpload/?id=951&userame=test HTTP/1.1
Accept-Encoding: gzip,deflate
Content-Type: multipart/form-data; boundary="----=_Part_9_23652504.1341953390382"
MIME-Version: 1.0

无法复制相同的行为

4

1 回答 1

1

您没有将 附加MultipartEntityHttpPost示例中的请求,这就是文件未上传的原因。也许尝试这样的事情:

HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);

MultipartEntity reqEntity = new MultipartEntity();

String requestBody = fileToString("src/main/resources/imageBodyPayload.xml");
reqEntity.addPart("request-body", new StringBody(requestBody));

FileBody fileBody = new FileBody(new File("C:\\sampler.jpg"));
reqEntity.addPart("upload-file", fileBody);

HttpParams parameters = new BasicHttpParams();
parameters.setLongParameter("id", 951);
parameters.setParameter("username", "test");

httppost.setParams(parameters);
httppost.setEntity(reqEntity);

HttpResponse response = httpclient.execute(httppost);

我不知道在你的情况下“request-body”的值是什么,但是 multipart/form-data 请求的每个部分都需要有一个名称,所以如果你试图发送一个文件和一些 XML单个请求,您需要同时提供文件部分和 XML 部分名称。

“multipart/form-data”消息包含一系列部分,每个部分代表一个成功的控件。每个部分都应包含一个 name 属性,指定相应控件的控件名称。

http://www.w3.org/TR/html401/interact/forms.html#h-17.13.4.2

于 2012-08-23T21:55:10.410 回答