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我正在使用 XMPP 和 openfire 服务器为 iPhone 开发一个聊天应用程序，OpenFire 服务器正在存储用户之间的所有聊天记录，但是当我尝试检索特定用户的聊天记录时，我只得到日期和聊天消息的数量，但没有实际的短信

我已经在 openfire 上安装了用于消息归档的开放归档插件

这是我传递给 Openfire Server 的节 

    <iq type='get' id='pk1'>
    <list xmlns='urn:xmpp:archive'
    with='piyush@openfire'>
    <set xmlns='http://jabber.org/protocol/rsm'>
    <max>30</max>
    </set>
    </list>
    </iq>

这是我从服务器收到的结果

  <iq type="result" id="pk1" to="vivek@openfire/iphone">
  <list xmlns="urn:xmpp:archive">
  <chat with="piyush@openfire" start="2012-07-04T13:16:12.291Z"/>
  <chat with="piyush@openfire" start="2012-07-05T08:25:31.555Z"/>
  <chat with="piyush@openfire" start="2012-07-05T12:38:24.098Z"/>
  <set xmlns="http://jabber.org/protocol/rsm">
  <first index="0">15</first>
  <last>25</last>
  <count>3</count>
  </set>
  </list>
  </iq>

这是我想要的，也是我期望的结果

 <iq type='result' to='vivek@openfire/iphone' id='page1'>
 <chat xmlns='urn:xmpp:archive'
    with='piyush@openfire'
    start='2012-07-04T13:16:12.291Z'
    subject='She speaks!'
    version='4'>
<from secs='0'><body>Art thou not Romeo, and a Montague?</body></from>
<to secs='11'><body>Neither, fair saint, if either thee dislike.</body></to>
.
[98 more messages]
.
<from secs='9'><body>How cam'st thou hither, tell me, and wherefore?</body></from>
<set xmlns='http://jabber.org/protocol/rsm'>
  <first index='0'>0</first>
  <last>99</last>
  <count>217</count>
</set>

请帮助我得到想要的结果

谢谢

4

5 回答 5

16

您必须使用<retrieve>（请参阅http://xmpp.org/extensions/xep-0136.html<list> ）提出请求，然后您可以从收到的结果中花费特定时间。例如：

发送：

    <iq type='get' id='pk1'>
       <list xmlns='urn:xmpp:archive'
               with='piyush@openfire'>
        <set xmlns='http://jabber.org/protocol/rsm'>
            <max>30</max>
        </set>
      </list>
   </iq>

收到：

 <iq type="result" id="pk1" to="vivek@openfire/iphone">
     <list xmlns="urn:xmpp:archive">
      <chat with="piyush@openfire" start="2012-07-04T13:16:12.291Z"/>
      <chat with="piyush@openfire" start="2012-07-05T08:25:31.555Z"/>
      <chat with="piyush@openfire" start="2012-07-05T12:38:24.098Z"/>
      <set xmlns="http://jabber.org/protocol/rsm">
          <first index="0">15</first>
           <last>25</last>
           <count>3</count>
      </set>
    </list>
 </iq>

现在您选择starts 之一并发送（日期和时间必须准确）：

  <iq type='get' id='pk1'>
    <retrieve xmlns='urn:xmpp:archive'
        with='piyush@openfire''
        start='2012-07-04T13:16:12.291Z'>
     <set xmlns='http://jabber.org/protocol/rsm'>
       <max>100</max>
     </set>
    </retrieve>
 </iq>

您将收到类似这样的信息（取决于最大值 -> max=30，body=30）：

   <iq type='result' to='vivek@openfire/iphone' id='page1'>
      <chat xmlns='urn:xmpp:archive'
             with='piyush@openfire'
              start='2012-07-04T13:16:12.291Z'
            subject='She speaks!'
       version='4'>
         <from secs='0'><body>Art thou not Romeo, and a Montague?</body></from>
         <to secs='11'><body>Neither, fair saint, if either thee dislike.</body></to>
          .
          [28 more messages]
          .
         <from secs='9'><body>How cam'st thou hither, tell me, and therefore?           </body>   
         </from>
      <set xmlns='http://jabber.org/protocol/rsm'>
       <first index='0'>0</first>
       <last>29</last>
       <count></count>
     </set>
  <iq>
于 2012-09-26T13:42:58.433 回答
10

检索特定聊天时间

发送它以获取时间：

 NSXMLElement *iq1 = [NSXMLElement elementWithName:@"iq"];
 [iq1 addAttributeWithName:@"type" stringValue:@"get"];
 [iq1 addAttributeWithName:@"id" stringValue:@"pk1"];
 NSXMLElement *retrieve = [NSXMLElement elementWithName:@"list" xmlns:@"urn:xmpp:archive"];
 [retrieve addAttributeWithName:@"with" stringValue:@"amit@openfire"];
 NSXMLElement *set = [NSXMLElement elementWithName:@"set" xmlns:@"http://jabber.org/protocol/rsm"];
 NSXMLElement *max = [NSXMLElement elementWithName:@"max" stringValue:@"100"];
 [iq1 addChild:retrieve];
 [retrieve addChild:set];


 [set addChild:max];


 [xmppStream sendElement:iq1];

检索聊天记录

使用开始日期并发送：

 NSXMLElement *iq1 = [NSXMLElement elementWithName:@"iq"];
 [iq1 addAttributeWithName:@"type" stringValue:@"get"];
 [iq1 addAttributeWithName:@"id" stringValue:@"pk1"];

 NSXMLElement *retrieve = [NSXMLElement elementWithName:@"retrieve" xmlns:@"urn:xmpp:archive"];
 [retrieve addAttributeWithName:@"with" stringValue:@"amit@openfire"];
 [retrieve addAttributeWithName:@"start" stringValue:@"2013-11-18T05:11:53.460Z"];
 NSXMLElement *set = [NSXMLElement elementWithName:@"set" xmlns:@"http://jabber.org/protocol/rsm"];
 NSXMLElement *max = [NSXMLElement elementWithName:@"max" stringValue:@"100"];
 [iq1 addChild:retrieve];
 [retrieve addChild:set];
 [set addChild:max];
 [xmppStream sendElement:iq1];
于 2013-11-18T10:38:17.067 回答
1

首先，要从 openfire 检索聊天记录，您需要安装 Open Archive 插件，因为监控插件仅用于在管理面板上监控和记录聊天历史记录，因此一旦您安装 Open Archive，您将不会收到代码“500”的任何错误。

您可以从以下链接下载并学习安装 Open Archive。

https://nexus.reucon.com/content/repositories/opensource-snapshots/com/reucon/openfire/plugins/archive/

https://maven.reucon.com/projects/public/archive/

上述代码中的另一个问题是，当您在请求中提及开始标签时，它与具有确切时间戳的聊天匹配，这就是它返回错误代码“404”的原因。我从我的请求中省略了开始标记并编写了以下代码，该代码返回与用户的整个聊天历史记录。

NSXMLElement *iq1 = [NSXMLElement elementWithName:@"iq"];
[iq1 addAttributeWithName:@"type" stringValue:@"get"];
[iq1 addAttributeWithName:@"id" stringValue:@"pk1"];

NSXMLElement *retrieve = [NSXMLElement elementWithName:@"retrieve" xmlns:@"urn:xmpp:archive"];

[retrieve addAttributeWithName:@"with" stringValue:@"rahul@vishals-mac-pro.local"];
NSXMLElement *set = [NSXMLElement elementWithName:@"set" xmlns:@"http://jabber.org/protocol/rsm"];
NSXMLElement *max = [NSXMLElement elementWithName:@"max" stringValue:@"100"];

[iq1 addChild:retrieve];
[retrieve addChild:set];
[set addChild:max];
[[[self appDelegate] xmppStream] sendElement:iq1];

在这里，这将返回用户 Rahul 和当前登录用户之间的 XML 响应中的整个聊天历史记录。

有关更多详细信息，请参阅此博客http://question.ikende.com/question/363439343236313430

于 2015-06-18T06:03:24.337 回答
1

从 openfire 服务器获取归档消息的 Swift 版本请求：

func getArchieveMessages(){
        let iQ = DDXMLElement.elementWithName("iq")
        iQ.addAttributeWithName("type", stringValue: "get")
        iQ.addAttributeWithName("id", stringValue: "page1")
        let list = DDXMLElement.elementWithName("retrieve")
        list.addAttributeWithName("xmlns", stringValue: "urn:xmpp:archive")
        list.addAttributeWithName("with", stringValue: "partner@domain")
        let set = DDXMLElement.elementWithName("set")
        set.addAttributeWithName("xmlns", stringValue: "http://jabber.org/protocol/rsm")
        let max = DDXMLElement.elementWithName("max")
        max.addAttributeWithName("xmlns", stringValue: "http://jabber.org/protocol/rsm")
        //(max as! DDXMLElement).setStringValue("30")
        (set as! DDXMLElement).addChild(max as! DDXMLNode)
        list.addChild(set as! DDXMLNode)
        iQ.addChild(list as! DDXMLNode)
        xmppStream.sendElement(iQ as! DDXMLElement)
    }

回复：

func xmppStream(sender: XMPPStream!, didReceiveIQ iq: XMPPIQ!) -> Bool {
        let chat = iq.elementForName("chat")
        let chats = (chat as DDXMLElement).children()
        for chat in chats{
            let msg = chat
            let body = (msg as! DDXMLElement).elementForName("body")
            if body != nil{
                if body.stringValue() != nil{
                    //print(body.stringValue()!)
                    chatMessages.append(body.stringValue()!)
                    if msg.attributeForName("jid") == nil{
                        type.append("Send")
                    }
                    else{
                        type.append("Receive")
                    }
                }
            }
        }
        print("Did receive IQ")
        return false
    }

*with 是您要获取其存档消息的人的 jid

于 2016-10-27T05:10:51.240 回答
1

在 Swift 4 中获取归档消息的示例

声明并初始化变量 XMPPMessageArchivingCoreDataStorage 我在其中初始化 XMPPStream

var xmppMessageStorage: XMPPMessageArchivingCoreDataStorage?
var xmppMessageArchiving: XMPPMessageArchiving?

xmppMessageStorage = XMPPMessageArchivingCoreDataStorage.sharedInstance()
    xmppMessageArchiving = XMPPMessageArchiving(messageArchivingStorage: xmppMessageStorage)

    xmppMessageArchiving?.clientSideMessageArchivingOnly = true
    xmppMessageArchiving?.activate(stream)
    xmppMessageArchiving?.addDelegate(self, delegateQueue: DispatchQueue.main)

这样做，每当消息到达时，这将导致它被归档而无需执行任何其他操作。

然后，检索归档的消息

func RecibedMessageArchiving(idFriend: String) {

        let JabberIDFriend = idFriend   //id friend chat, example test1@example.com


        let moc = xmppMessageStorage?.mainThreadManagedObjectContext
        let entityDescription = NSEntityDescription.entity(forEntityName: "XMPPMessageArchiving_Message_CoreDataObject", in: moc!)
        let request = NSFetchRequest<NSFetchRequestResult>()
        let predicateFormat = "bareJidStr like %@ "
        let predicate = NSPredicate(format: predicateFormat, JabberIDFriend)

        request.predicate = predicate
        request.entity = entityDescription

        //jabberID id del usuario, cliente
        var jabberIDCliente = ""
        if let jabberj = globalChat.value(forKey: "jabberID"){
            jabberIDCliente = jabberj as! String
        }


        do {
            let results = try moc?.fetch(request)

            for message: XMPPMessageArchiving_Message_CoreDataObject? in results as? [XMPPMessageArchiving_Message_CoreDataObject?] ?? [] {

                var element: DDXMLElement!
                do {
                    element = try DDXMLElement(xmlString: (message as AnyObject).messageStr)
                } catch _ {
                    element = nil
                }

                let body: String
                let sender: String
                let date: NSDate
                let isIncomings: Bool
于 2018-11-22T19:04:00.927 回答