我是一个相当新的程序员,所以请多多包涵。我正在使用 VC++ 2008。
我从我的程序中收到此错误:
z projection.exe 中 0x68bce2ba (msvcp90d.dll) 处未处理的异常:0xC0000005:访问冲突写入位置 0x00630067。
然后计算机将我带到这一页代码,它看起来相当混乱,而且我绝对不是写的。它指出这部分代码是有问题的代码(由“<-computer points to this line”标记):
public:
_CRTIMP2_PURE static size_t __CLRCALL_OR_CDECL _Getcat(const facet ** = 0,
const locale * = 0)
{ // get category value, or -1 if no corresponding C category
return ((size_t)(-1));
}
_CRTIMP2_PURE void __CLR_OR_THIS_CALL _Incref()
{ // safely increment the reference count
_BEGIN_LOCK(_LOCK_LOCALE)
if (_Refs < (size_t)(-1))
++_Refs; <-computer points to this line
_END_LOCK()
}
_CRTIMP2_PURE facet *__CLR_OR_THIS_CALL _Decref()
{ // safely decrement the reference count, return this when dead
_BEGIN_LOCK(_LOCK_LOCALE)
if (0 < _Refs && _Refs < (size_t)(-1))
--_Refs;
return (_Refs == 0 ? this : 0);
_END_LOCK()
}
我已将其缩小到我自己的程序中可能导致崩溃的代码行(以“index”开头的第 4 行代码,也是 stage = 1):
stringstream index;
string fileName = "";
index.str("");//
index << setw( 3 ) << setfill( '0' ) << stage - 1;
fileName = "positive Z topography-" + index.str() + ".txt";
令我困惑的是,我从我编写的另一个程序中复制并粘贴了这段代码,该程序已经运行了数百次,从来没有遇到过任何麻烦。
编辑:这是整个代码。
#include <iostream>
#include <fstream>
#include <sstream>
#include <string>
#include <iomanip>
using namespace std;
int main ()
{
int dim = 100;
int steps = 9; //step 0 = 1, steps = actual steps + 1
int spread = 5; //number of points averaged to get a slope, must be an odd number
int halfSpread = (spread - 1)/2; //redefine for eazier use in program (better efficency)
char * partMap = new char [dim * dim * dim]; // cad data
// positive and negitive denote the x direction the check is moving in. Positive is 0 -> x, negitive is x -> 0.
unsigned short int * positiveProjection = new unsigned short int [dim * dim]; //projection arrays
unsigned short int * negitiveProjection = new unsigned short int [dim * dim];
unsigned short int * negitiveThickness = new unsigned short int [dim * dim];
double * negitiveXGradient = new double [dim * dim];
double * negitiveYGradient = new double [dim * dim];
stringstream index;
string fileName;
ifstream txtFile;
txtFile.open("3D CAD Part.txt");
txtFile.read(partMap, dim * dim * dim);
txtFile.close();
for (int stage = 1; stage < steps; stage++)
{
cout << "stage " << stage << endl;
//z axis projections
//projection order is along x then along y, during each step, along z in both directions
int k = 0; // z axis loop variable
for (int j = 0; j < dim; j++)
{
for (int i = 0; i < dim; i++)
{
k = 0;
while ((k != dim) && partMap[dim * ((dim - 1 - k) + dim * i) + j] < stage)
k++;
positiveProjection[dim * k + j] = k;
k = dim;
while ((k != 0) && partMap[dim * ((dim - 1 - (k - 1)) + dim * i) + j] < stage)
k--;
negitiveProjection[dim * k + j] = i;
while ((k != 0) && partMap[dim * ((dim - 1 - (k - 1)) + dim * i) + j] >= stage)
k--;
negitiveThickness[dim * k + j] = negitiveProjection[dim * k + j] - k;
}
}
// negitive dz/dx gradient
for (int j = 0; j < dim; j++)
{
//first loop to handle the first edge gradients
for (int i = 0; i < halfSpread; i++)
negitiveXGradient[(j * dim) + i] = (double(negitiveProjection[(j * dim) + halfSpread + i]) - double(negitiveProjection[j * dim]))/(halfSpread + i); // untested
//second loop to handle the main middle section
for (int i = halfSpread; i < dim - halfSpread; i++)
negitiveXGradient[(j * dim) + i] = (double(negitiveProjection[(j * dim) + i + halfSpread]) - double(negitiveProjection[(j * dim) + i - halfSpread]))/ (spread - 1); // untested
//third loop to handle the end edge gradients
for (int i = dim - halfSpread; i < dim; i++)
negitiveXGradient[(j * dim) + i] = (double(negitiveProjection[(j * dim) + dim - 1]) - double(negitiveProjection[j * dim + i - halfSpread]))/((dim - 1) - i + halfSpread); // untested
}
// negitive dz/dy gradient
for (int i = 0; i < dim; i++)
{
//first loop to handle the first edge gradients
for (int j = 0; j < halfSpread; j++)
negitiveYGradient[(j * dim) + i] = (double(negitiveProjection[((j + halfSpread) * dim) + i]) - double(negitiveProjection[i]))/(halfSpread + j); // untested
//second loop to handle the main middle section
for (int j = halfSpread; j < dim - halfSpread; j++)
negitiveYGradient[(j * dim) + i] = (double(negitiveProjection[((j + halfSpread) * dim) + i]) - double(negitiveProjection[((j - halfSpread) * dim) + i]))/ (spread - 1); // untested
//third loop to handle the end edge gradients
for (int j = dim - halfSpread; j < dim; j++)
negitiveYGradient[(j * dim) + i] = (double(negitiveProjection[(dim * (dim - 1)) + i]) - double(negitiveProjection[((j - halfSpread) * dim) + i]))/((dim - 1) - j + halfSpread); // untested
}
fileName = ""; // reset string and stringstream
index.str("");//
index << setw( 3 ) << setfill( '0' ) << stage - 1; // set index, index is -1 of stage due to the program structure
fileName = "positive Z topography-" + index.str() + ".txt";
ofstream outputFile1(fileName.c_str(), std::ios::binary | std::ios::out);
outputFile1.write(reinterpret_cast<const char*>(positiveProjection), streamsize(dim * dim * sizeof(unsigned short int)));
outputFile1.close();
fileName = "negitive Z topography-" + index.str() + ".txt";
ofstream outputFile2(fileName.c_str(), std::ios::binary | std::ios::out);
outputFile2.write(reinterpret_cast<const char*>(negitiveProjection), streamsize(dim * dim * sizeof(unsigned short int)));
outputFile2.close();
fileName = "negitive Z thickness-" + index.str() + ".txt";
ofstream outputFile4(fileName.c_str(), std::ios::binary | std::ios::out);
outputFile4.write(reinterpret_cast<const char*>(negitiveThickness), streamsize(dim * dim * sizeof(unsigned short int)));
outputFile4.close();
fileName = "negitive Z X gradient-" + index.str() + ".txt";
ofstream outputFile5(fileName.c_str(), std::ios::binary | std::ios::out);
outputFile5.write(reinterpret_cast<const char*>(negitiveXGradient), streamsize(dim * dim * sizeof(double)));
outputFile5.close();
fileName = "negitive Z Y gradient-" + index.str() + ".txt";
ofstream outputFile6(fileName.c_str(), std::ios::binary | std::ios::out);
outputFile6.write(reinterpret_cast<const char*>(negitiveYGradient), streamsize(dim * dim * sizeof(double)));
outputFile6.close();
}
}
好的,在我开始将结果输出到硬盘的最后一段代码之前,一切都很好。我使用了 VC++ 中的断点,并且在错误之前成功通过的最后一个断点位于前面提到的点(我发布的第二个代码块)。显然 HTML 也不喜欢我的 c++ 代码。
哦,还有,省去遍历循环的麻烦......它们应该没问题......那里有十几个循环,你不必担心它们发生了什么,它们非常安全。我只有最后一块有问题。