87

我的客户想在 Instagram、Twitter、Facebook 上分享一张图片。

我已经完成了 Twitter 和 Facebook,但没有在互联网上找到任何 API 或任何东西来在 Instagram 上分享图像。是否可以在 Instagram 上分享图片?如果是,那怎么办?

当我查看 Instagram 的开发者网站时,我发现了 Ruby on Rails 和 Python 的库。但是没有iOS Sdk的文档

我已根据 instagram.com/developer 从 instagram 获得令牌,但现在不知道下一步如何与 instagram 图像共享。

4

18 回答 18

70

最后我得到了答案。您不能直接在 Instagram 上发布图片。您必须使用 UIDocumentInteractionController 重新分配您的图像。

@property (nonatomic, retain) UIDocumentInteractionController *dic;    

CGRect rect = CGRectMake(0 ,0 , 0, 0);
UIGraphicsBeginImageContextWithOptions(self.view.bounds.size, self.view.opaque, 0.0);
[self.view.layer renderInContext:UIGraphicsGetCurrentContext()];
UIGraphicsEndImageContext();
NSString  *jpgPath = [NSHomeDirectory() stringByAppendingPathComponent:@"Documents/test.igo"];

NSURL *igImageHookFile = [[NSURL alloc] initWithString:[[NSString alloc] initWithFormat:@"file://%@", jpgPath]];
self.dic.UTI = @"com.instagram.photo";
self.dic = [self setupControllerWithURL:igImageHookFile usingDelegate:self];
self.dic=[UIDocumentInteractionController interactionControllerWithURL:igImageHookFile];
[self.dic presentOpenInMenuFromRect: rect    inView: self.view animated: YES ];


- (UIDocumentInteractionController *) setupControllerWithURL: (NSURL*) fileURL usingDelegate: (id <UIDocumentInteractionControllerDelegate>) interactionDelegate {
     UIDocumentInteractionController *interactionController = [UIDocumentInteractionController interactionControllerWithURL: fileURL];
     interactionController.delegate = interactionDelegate;
     return interactionController;
}

注意:一旦您重定向到 Instagram 应用程序,您将无法返回您的应用程序。你必须再次打开你的应用程序

从这里下载源代码

于 2012-07-16T09:17:50.923 回答
27

这是将图像+标题文本上传到 Instagram 的完整测试代码。

in.h 文件

//Instagram
@property (nonatomic, retain) UIDocumentInteractionController *documentController;

-(void)instaGramWallPost
{
            NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"];
            if([[UIApplication sharedApplication] canOpenURL:instagramURL]) //check for App is install or not
            {
                NSData *imageData = UIImagePNGRepresentation(imge); //convert image into .png format.
                NSFileManager *fileManager = [NSFileManager defaultManager];//create instance of NSFileManager
                NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES); //create an array and store result of our search for the documents directory in it
                NSString *documentsDirectory = [paths objectAtIndex:0]; //create NSString object, that holds our exact path to the documents directory
                NSString *fullPath = [documentsDirectory stringByAppendingPathComponent:[NSString stringWithFormat:@"insta.igo"]]; //add our image to the path
                [fileManager createFileAtPath:fullPath contents:imageData attributes:nil]; //finally save the path (image)
                NSLog(@"image saved");

                CGRect rect = CGRectMake(0 ,0 , 0, 0);
                UIGraphicsBeginImageContextWithOptions(self.view.bounds.size, self.view.opaque, 0.0);
                [self.view.layer renderInContext:UIGraphicsGetCurrentContext()];
                UIGraphicsEndImageContext();
                NSString *fileNameToSave = [NSString stringWithFormat:@"Documents/insta.igo"];
                NSString  *jpgPath = [NSHomeDirectory() stringByAppendingPathComponent:fileNameToSave];
                NSLog(@"jpg path %@",jpgPath);
                NSString *newJpgPath = [NSString stringWithFormat:@"file://%@",jpgPath];
                NSLog(@"with File path %@",newJpgPath);
                NSURL *igImageHookFile = [[NSURL alloc]initFileURLWithPath:newJpgPath];
                NSLog(@"url Path %@",igImageHookFile);

                self.documentController.UTI = @"com.instagram.exclusivegram";
                self.documentController = [self setupControllerWithURL:igImageHookFile usingDelegate:self];
                self.documentController=[UIDocumentInteractionController interactionControllerWithURL:igImageHookFile];
                NSString *caption = @"#Your Text"; //settext as Default Caption
                self.documentController.annotation=[NSDictionary dictionaryWithObjectsAndKeys:[NSString stringWithFormat:@"%@",caption],@"InstagramCaption", nil];
                [self.documentController presentOpenInMenuFromRect:rect inView: self.view animated:YES];
            }
            else
            {
                 NSLog (@"Instagram not found");
            }
}

- (UIDocumentInteractionController *) setupControllerWithURL: (NSURL*) fileURL usingDelegate: (id <UIDocumentInteractionControllerDelegate>) interactionDelegate {
    NSLog(@"file url %@",fileURL);
    UIDocumentInteractionController *interactionController = [UIDocumentInteractionController interactionControllerWithURL: fileURL];
    interactionController.delegate = interactionDelegate;

    return interactionController;
}

或者

-(void)instaGramWallPost
{
    NSURL *myURL = [NSURL URLWithString:@"Your image url"];
    NSData * imageData = [[NSData alloc] initWithContentsOfURL:myURL];
    UIImage *imgShare = [[UIImage alloc] initWithData:imageData];

    NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"];

    if([[UIApplication sharedApplication] canOpenURL:instagramURL]) //check for App is install or not
    {
        UIImage *imageToUse = imgShare;
        NSString *documentDirectory=[NSHomeDirectory() stringByAppendingPathComponent:@"Documents"];
        NSString *saveImagePath=[documentDirectory stringByAppendingPathComponent:@"Image.igo"];
        NSData *imageData=UIImagePNGRepresentation(imageToUse);
        [imageData writeToFile:saveImagePath atomically:YES];
        NSURL *imageURL=[NSURL fileURLWithPath:saveImagePath];
        self.documentController=[[UIDocumentInteractionController alloc]init];
        self.documentController = [UIDocumentInteractionController interactionControllerWithURL:imageURL];
        self.documentController.delegate = self;
        self.documentController.annotation = [NSDictionary dictionaryWithObjectsAndKeys:[NSString stringWithFormat:@"Testing"], @"InstagramCaption", nil];
        self.documentController.UTI = @"com.instagram.exclusivegram";
        UIViewController *vc = [UIApplication sharedApplication].keyWindow.rootViewController;
        [self.documentController presentOpenInMenuFromRect:CGRectMake(1, 1, 1, 1) inView:vc.view animated:YES];
    }
    else {
        DisplayAlertWithTitle(@"Instagram not found", @"")
    }
}

并将其写入 .plist

<key>LSApplicationQueriesSchemes</key>
    <array>
        <string>instagram</string>
    </array>
于 2015-02-02T07:08:53.853 回答
22

您可以使用 Instagram url 方案提供的一种

在此处输入图像描述

  1. Instagram官方文档在这里

  2. 与 UIDocumentInteractionController 共享

     final class InstagramPublisher : NSObject {
    
     private var documentsController:UIDocumentInteractionController = UIDocumentInteractionController()
    
     func postImage(image: UIImage, view: UIView, result:((Bool)->Void)? = nil) {
         guard let instagramURL = NSURL(string: "instagram://app") else {
             if let result = result {
                 result(false)
             }
         return
     }
         if UIApplication.sharedApplication().canOpenURL(instagramURL) {
             let jpgPath = (NSTemporaryDirectory() as NSString).stringByAppendingPathComponent("instagrammFotoToShareName.igo")
             if let image = UIImageJPEGRepresentation(image, 1.0) {
                 image.writeToFile(jpgPath, atomically: true)
                 let fileURL = NSURL.fileURLWithPath(jpgPath)
                 documentsController.URL = fileURL
                 documentsController.UTI = "com.instagram.exclusivegram"
                 documentsController.presentOpenInMenuFromRect(view.bounds, inView: view, animated: true)
                 if let result = result {
                     result(true)
                 }
             } else if let result = result {
                 result(false)
             }
         } else {
             if let result = result {
                 result(false)
             }
         }
         }
     }
    
  3. 通过直接重定向共享

     import Photos
    
     final class InstagramPublisher : NSObject {
    
     func postImage(image: UIImage, result:((Bool)->Void)? = nil) {
     guard let instagramURL = NSURL(string: "instagram://app") else {
         if let result = result {
             result(false)
         }
         return
     }
    
     let image = image.scaleImageWithAspectToWidth(640)
    
     do {
         try PHPhotoLibrary.sharedPhotoLibrary().performChangesAndWait {
             let request = PHAssetChangeRequest.creationRequestForAssetFromImage(image)
    
             let assetID = request.placeholderForCreatedAsset?.localIdentifier ?? ""
             let shareURL = "instagram://library?LocalIdentifier=" + assetID
    
             if UIApplication.sharedApplication().canOpenURL(instagramURL) {
                 if let urlForRedirect = NSURL(string: shareURL) {
                     UIApplication.sharedApplication().openURL(urlForRedirect)
                 }
             }
         }
     } catch {
         if let result = result {
             result(false)
         }
     }
     }
     }
    
  4. 将照片调整为推荐尺寸的扩展

     import UIKit
    
     extension UIImage {
         // MARK: - UIImage+Resize
    
         func scaleImageWithAspectToWidth(toWidth:CGFloat) -> UIImage {
             let oldWidth:CGFloat = size.width
             let scaleFactor:CGFloat = toWidth / oldWidth
    
             let newHeight = self.size.height * scaleFactor
             let newWidth = oldWidth * scaleFactor;
    
             UIGraphicsBeginImageContext(CGSizeMake(newWidth, newHeight))
             drawInRect(CGRectMake(0, 0, newWidth, newHeight))
             let newImage = UIGraphicsGetImageFromCurrentImageContext()
             UIGraphicsEndImageContext()
             return newImage
         }
     }
    
  5. 不要忘记在 plist 中添加所需的方案

  <key>LSApplicationQueriesSchemes</key>
  <array>
       <string>instagram</string> 
  </array>
于 2016-10-31T07:28:56.080 回答
14

希望这个答案能解决您的疑问。这将直接在 Instagram 而不是相机中打开库文件夹。

NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"];
if ([[UIApplication sharedApplication] canOpenURL:instagramURL])
{
    NSURL *videoFilePath = [NSURL URLWithString:[NSString stringWithFormat:@"%@",[request downloadDestinationPath]]]; // Your local path to the video
    NSString *caption = @"Some Preloaded Caption";
    ALAssetsLibrary *library = [[ALAssetsLibrary alloc] init];
    [library writeVideoAtPathToSavedPhotosAlbum:videoFilePath completionBlock:^(NSURL *assetURL, NSError *error) {
        NSString *escapedString   = [self urlencodedString:videoFilePath.absoluteString];
        NSString *escapedCaption  = [self urlencodedString:caption];
        NSURL *instagramURL = [NSURL URLWithString:[NSString stringWithFormat:@"instagram://library?AssetPath=%@&InstagramCaption=%@",escapedString,escapedCaption]];
        if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) {
            [[UIApplication sharedApplication] openURL:instagramURL];
        }
    }];
于 2014-12-30T09:11:11.900 回答
10

如果您不想使用 UIDocumentInteractionController

import Photos

...

func postImageToInstagram(image: UIImage) {
        UIImageWriteToSavedPhotosAlbum(image, self, #selector(SocialShare.image(_:didFinishSavingWithError:contextInfo:)), nil)
    }
    func image(image: UIImage, didFinishSavingWithError error: NSError?, contextInfo:UnsafePointer<Void>) {
        if error != nil {
            print(error)
        }

        let fetchOptions = PHFetchOptions()
        fetchOptions.sortDescriptors = [NSSortDescriptor(key: "creationDate", ascending: false)]
        let fetchResult = PHAsset.fetchAssetsWithMediaType(.Image, options: fetchOptions)
        if let lastAsset = fetchResult.firstObject as? PHAsset {
            let localIdentifier = lastAsset.localIdentifier
            let u = "instagram://library?LocalIdentifier=" + localIdentifier
            let url = NSURL(string: u)!
            if UIApplication.sharedApplication().canOpenURL(url) {
                UIApplication.sharedApplication().openURL(NSURL(string: u)!)
            } else {
                let alertController = UIAlertController(title: "Error", message: "Instagram is not installed", preferredStyle: .Alert)
                alertController.addAction(UIAlertAction(title: "OK", style: .Default, handler: nil))
                self.presentViewController(alertController, animated: true, completion: nil)
            }

        }
    }
于 2016-07-24T09:24:02.640 回答
9

对于 iOS 6 及更高版本,您可以使用此 UIActivity 将图像上传到 Instagram,它使用 iOS 挂钩具有相同的工作流程,但简化了开发:

https://github.com/coryalder/DMActivityInstagram

于 2013-01-30T11:31:47.990 回答
6

这是我详细实施的正确答案。在 .h 文件中

 UIImageView *imageMain;
 @property (nonatomic, strong) UIDocumentInteractionController *documentController;

in.m 文件只写

 NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"];
 if([[UIApplication sharedApplication] canOpenURL:instagramURL])
 {
      CGFloat cropVal = (imageMain.image.size.height > imageMain.image.size.width ? imageMain.image.size.width : imageMain.image.size.height);

      cropVal *= [imageMain.image scale];

      CGRect cropRect = (CGRect){.size.height = cropVal, .size.width = cropVal};
      CGImageRef imageRef = CGImageCreateWithImageInRect([imageMain.image CGImage], cropRect);

      NSData *imageData = UIImageJPEGRepresentation([UIImage imageWithCGImage:imageRef], 1.0);
      CGImageRelease(imageRef);

      NSString *writePath = [NSTemporaryDirectory() stringByAppendingPathComponent:@"instagram.igo"];
      if (![imageData writeToFile:writePath atomically:YES]) {
      // failure
           NSLog(@"image save failed to path %@", writePath);
           return;
      } else {
      // success.
      }

      // send it to instagram.
      NSURL *fileURL = [NSURL fileURLWithPath:writePath];
      self.documentController = [UIDocumentInteractionController interactionControllerWithURL:fileURL];
      self.documentController.delegate = self;
      [self.documentController setUTI:@"com.instagram.exclusivegram"];
      [self.documentController setAnnotation:@{@"InstagramCaption" : @"We are making fun"}];
      [self.documentController presentOpenInMenuFromRect:CGRectMake(0, 0, 320, 480) inView:self.view animated:YES];
 }
 else
 {
      NSLog (@"Instagram not found");

 }

你肯定会得到结果。例如,您会从底部看到带有 instagram 图像的弹出窗口。单击它并玩得开心。

于 2014-08-11T11:54:46.483 回答
5

我在我的应用程序中尝试了这个,它运行良好(Swift)

import Foundation

import UIKit

class InstagramManager: NSObject, UIDocumentInteractionControllerDelegate {

    private let kInstagramURL = "instagram://"
    private let kUTI = "com.instagram.exclusivegram"
    private let kfileNameExtension = "instagram.igo"
    private let kAlertViewTitle = "Error"
    private let kAlertViewMessage = "Please install the Instagram application"

    var documentInteractionController = UIDocumentInteractionController()

    // singleton manager
    class var sharedManager: InstagramManager {
        struct Singleton {
            static let instance = InstagramManager()
        }
        return Singleton.instance
    }

    func postImageToInstagramWithCaption(imageInstagram: UIImage, instagramCaption: String, view: UIView) {
        // called to post image with caption to the instagram application

        let instagramURL = NSURL(string: kInstagramURL)
        if UIApplication.sharedApplication().canOpenURL(instagramURL!) {
            let jpgPath = (NSTemporaryDirectory() as NSString).stringByAppendingPathComponent(kfileNameExtension)
            UIImageJPEGRepresentation(imageInstagram, 1.0)!.writeToFile(jpgPath, atomically: true)
            let rect = CGRectMake(0,0,612,612)
            let fileURL = NSURL.fileURLWithPath(jpgPath)
            documentInteractionController.URL = fileURL
            documentInteractionController.delegate = self
            documentInteractionController.UTI = kUTI

            // adding caption for the image
            documentInteractionController.annotation = ["InstagramCaption": instagramCaption]
            documentInteractionController.presentOpenInMenuFromRect(rect, inView: view, animated: true)
        }
        else {

            // alert displayed when the instagram application is not available in the device
            UIAlertView(title: kAlertViewTitle, message: kAlertViewMessage, delegate:nil, cancelButtonTitle:"Ok").show()
        }
    }
}


 func sendToInstagram(){

     let image = postImage

             InstagramManager.sharedManager.postImageToInstagramWithCaption(image!, instagramCaption: "\(description)", view: self.view)

 }
于 2016-02-02T10:38:59.553 回答
2

这是正确的答案。您不能直接在 Instagram 上发布图片。您需要使用 UIDocumentInteractionController 重定向到 Instagram...

NSString* imagePath = [NSString stringWithFormat:@"%@/instagramShare.igo", [NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) lastObject]];
[[NSFileManager defaultManager] removeItemAtPath:imagePath error:nil];
    
UIImage *instagramImage = [UIImage imageNamed:@"imagename you want to share"];
[UIImagePNGRepresentation(instagramImage) writeToFile:imagePath atomically:YES];
NSLog(@"Image Size >>> %@", NSStringFromCGSize(instagramImage.size));
    
self.dic=[UIDocumentInteractionController interactionControllerWithURL:[NSURL fileURLWithPath:imagePath]];
self.dic.delegate = self;
self.dic.UTI = @"com.instagram.exclusivegram";
[self.dic presentOpenInMenuFromRect: self.view.frame inView:self.view animated:YES ];

注意:一旦您重定向到 Instagram 应用程序,您将无法返回您的应用程序。你必须再次打开你的应用程序

于 2014-01-03T09:02:52.860 回答
2

您可以在不使用 UIDocumentInteractionController 的情况下执行此操作,并使用以下 3 种方法直接访问 Instagram:

它就像所有其他著名的应用程序一样工作。代码是用 Objective c 编写的,因此您可以根据需要将其翻译成 swift。您需要做的是将图像保存到设备并使用 URLScheme

将此添加到您的 .m 文件中

#import <Photos/Photos.h>

首先,您需要使用此方法将 UIImage 保存到设备:

-(void)savePostsPhotoBeforeSharing
{
    UIImageWriteToSavedPhotosAlbum([UIImage imageNamed:@"image_file_name.jpg"], self, @selector(image:didFinishSavingWithError:contextInfo:), NULL);
}

此方法是将图像保存到您的设备的回调:

- (void)image:(UIImage *)image didFinishSavingWithError:(NSError *)error contextInfo: (void *) contextInfo;
{
    [self sharePostOnInstagram];

}

图片保存到设备后,需要查询刚刚保存的图片,作为PHAsset获取

-(void)sharePostOnInstagram
{
    PHFetchOptions *fetchOptions = [PHFetchOptions new];
    fetchOptions.sortDescriptors = @[[NSSortDescriptor sortDescriptorWithKey:@"creationDate" ascending:NO],];
    __block PHAsset *assetToShare;
    PHFetchResult *result = [PHAsset fetchAssetsWithMediaType:PHAssetMediaTypeImage options:fetchOptions];
    [result enumerateObjectsUsingBlock:^(PHAsset *asset, NSUInteger idx, BOOL *stop) {
        assetToShare = asset;


    }];


    if([assetToShare isKindOfClass:[PHAsset class]])
    {
        NSString *localIdentifier = assetToShare.localIdentifier;
        NSString *urlString = [NSString stringWithFormat:@"instagram://library?LocalIdentifier=%@",localIdentifier];
        NSURL *instagramURL = [NSURL URLWithString:urlString];
        if ([[UIApplication sharedApplication] canOpenURL: instagramURL])
        {
            [[UIApplication sharedApplication] openURL: instagramURL];
        } else
        {
            // can not share with whats app
            NSLog(@"No instagram installed");
        }

    }
}

别忘了把它放在你的 info.plist 下LSApplicationQueriesSchemes

<string>instagram</string>

于 2017-03-28T08:25:20.627 回答
1
- (void) shareImageWithInstagram
{
    NSURL *instagramURL = [NSURL URLWithString:@"instagram://"];
    if ([[UIApplication sharedApplication] canOpenURL:instagramURL])
    {
        UICachedFileMgr* mgr = _gCachedManger;
        UIImage* photoImage = [mgr imageWithUrl:_imageView.image];
        NSData* imageData = UIImagePNGRepresentation(photoImage);
        NSString* captionString = [NSString  stringWithFormat:@"ANY_TAG",];
        NSString* imagePath = [UIUtils documentDirectoryWithSubpath:@"image.igo"];
        [imageData writeToFile:imagePath atomically:NO];
        NSURL* fileURL = [NSURL fileURLWithPath:[NSString stringWithFormat:@"file://%@",imagePath]];

        self.docFile = [[self setupControllerWithURL:fileURL usingDelegate:self]retain];
        self.docFile.annotation = [NSDictionary dictionaryWithObject: captionString
                                                     forKey:@"InstagramCaption"];
        self.docFile.UTI = @"com.instagram.photo";

        // OPEN THE HOOK
        [self.docFile presentOpenInMenuFromRect:self.view.frame inView:self.view animated:YES];
    }
    else
    {
        [UIUtils messageAlert:@"Instagram not installed in this device!\nTo share image please install instagram." title:nil delegate:nil];
    }
}

我在我的应用程序中尝试了这个,它肯定会工作

于 2014-02-04T11:57:57.493 回答
1

至于我,这里描述的最好和最简单的方法从我的 iOS 应用程序将照片分享到 Instagram

您需要使用 .igo 格式将图像保存在设备上,然后使用“UIDocumentInteractionController”发送本地路径 Instagram 应用程序。不要忘记设置“UIDocumentInteractionControllerDelegate”

我的建议是添加如下内容:

NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"];
if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) 
{
 <your code>
}
于 2014-12-09T17:07:37.950 回答
1
NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"];

if ([[UIApplication sharedApplication] canOpenURL:instagramURL])
{

    NSString  *jpgPath = [NSHomeDirectory() stringByAppendingPathComponent:[NSString stringWithFormat:@"Documents/Insta_Images/%@",@"shareImage.png"]];


    NSURL *igImageHookFile = [[NSURL alloc] initWithString:[[NSString alloc] initWithFormat:@"file://%@", jpgPath]];


    docController.UTI = @"com.instagram.photo";

    docController = [self setupControllerWithURL:igImageHookFile usingDelegate:self];

    docController =[UIDocumentInteractionController interactionControllerWithURL:igImageHookFile];

    docController.delegate=self;

    [docController presentOpenInMenuFromRect:CGRectMake(0 ,0 , 612, 612) inView:self.view animated:YES];
于 2015-06-12T09:16:06.110 回答
1

我注意到,如果您将URL指向图像activityItems而不是UIImageCopy to Instagram活动项本身就会出现,并且您无需执行任何其他操作。请注意,String里面的对象activityItems将被丢弃,并且无法在 Instagram 中预填充标题。如果您仍想提示用户发布特定标题,则需要创建自定义活动,在其中将该文本复制到剪贴板并让用户知道它,就像在这个 gist中一样。

于 2018-01-11T19:03:37.417 回答
1
    @import Photos;

    -(void)shareOnInstagram:(UIImage*)imageInstagram {

        [self authorizePHAssest:imageInstagram];
    }

    -(void)authorizePHAssest:(UIImage *)aImage{

        PHAuthorizationStatus status = [PHPhotoLibrary authorizationStatus];

        if (status == PHAuthorizationStatusAuthorized) {
            // Access has been granted.
            [self savePostsPhotoBeforeSharing:aImage];
        }

        else if (status == PHAuthorizationStatusDenied) {
            // Access has been denied.
        }

        else if (status == PHAuthorizationStatusNotDetermined) {

            // Access has not been determined.
            [PHPhotoLibrary requestAuthorization:^(PHAuthorizationStatus status) {

                if (status == PHAuthorizationStatusAuthorized) {
                    // Access has been granted.
                    [self savePostsPhotoBeforeSharing:aImage];
                }
            }];
        }

        else if (status == PHAuthorizationStatusRestricted) {
            // Restricted access - normally won't happen.
        }
    }
    -(void)saveImageInDeviceBeforeSharing:(UIImage *)aImage
    {
        UIImageWriteToSavedPhotosAlbum(aImage, self, @selector(image:didFinishSavingWithError:contextInfo:), NULL);
    }

    - (void)image:(UIImage *)image didFinishSavingWithError:(NSError *)error contextInfo: (void *) contextInfo;
    {
        if (error == nil){
            [self sharePostOnInstagram];
        }
    }

    -(void)shareImageOnInstagram
    {
        PHFetchOptions *fetchOptions = [PHFetchOptions new];
        fetchOptions.sortDescriptors = @[[NSSortDescriptor sortDescriptorWithKey:@"creationDate" ascending:false]];
        PHFetchResult *result = [PHAsset fetchAssetsWithMediaType:PHAssetMediaTypeImage options:fetchOptions];

        __block PHAsset *assetToShare = [result firstObject];

        if([assetToShare isKindOfClass:[PHAsset class]])
        {
            NSString *localIdentifier = assetToShare.localIdentifier;
            NSString *urlString = [NSString stringWithFormat:@"instagram://library?LocalIdentifier=%@",localIdentifier];
            NSURL *instagramURL = [NSURL URLWithString:urlString];
            if ([[UIApplication sharedApplication] canOpenURL: instagramURL])
            {
                [[UIApplication sharedApplication] openURL:instagramURL options:@{} completionHandler:nil];
            } else
            {
                NSLog(@"No instagram installed");
            }
        }
    }

注意:- IMP TODO:- 在 Info.plist 中添加以下键

<key>LSApplicationQueriesSchemes</key>
<array>
<string>instagram</string>
</array>
于 2019-02-15T11:53:17.513 回答
0

我使用了这段代码:

    NSString* filePathStr = [[NSBundle mainBundle] pathForResource:@"UMS_social_demo" ofType:@"png"];
NSURL* fileUrl = [NSURL fileURLWithPath:filePathStr];

NSString  *jpgPath = [NSHomeDirectory() stringByAppendingPathComponent:@"Documents/test.igo"];
[[NSData dataWithContentsOfURL:fileUrl] writeToFile:jpgPath atomically:YES];

NSURL* documentURL = [NSURL URLWithString:[NSString stringWithFormat:@"file://%@", jpgPath]];

UIDocumentInteractionController *interactionController = [UIDocumentInteractionController interactionControllerWithURL: documentURL];
self.interactionController = interactionController;
interactionController.delegate = self;
interactionController.UTI = @"com.instagram.photo";
CGRect rect = CGRectMake(0 ,0 , 0, 0);
[interactionController presentOpenInMenuFromRect:rect inView:self.view animated:YES];
于 2016-08-25T06:53:30.173 回答
0
-(void)shareOnInstagram {

    CGRect rect = CGRectMake(self.view.frame.size.width*0.375 ,self.view.frame.size.height/2 , 0, 0);



    NSString * saveImagePath = [NSHomeDirectory() stringByAppendingPathComponent:@"Documents/ShareInstragramImage.igo"];

    [UIImagePNGRepresentation(_image) writeToFile:saveImagePath atomically:YES];

    NSURL *igImageHookFile = [[NSURL alloc] initWithString:[[NSString alloc] initWithFormat:@"file://%@", saveImagePath]];

    self.documentController=[UIDocumentInteractionController interactionControllerWithURL:igImageHookFile];

    self.documentController.UTI = @"com.instagram.exclusivegram";
    self.documentController = [self setupControllerWithURL:igImageHookFile usingDelegate:self];

    [self.documentController presentOpenInMenuFromRect: rect    inView: self.view animated: YES ];

}

-(UIDocumentInteractionController *) setupControllerWithURL: (NSURL*) fileURL usingDelegate: (id <UIDocumentInteractionControllerDelegate>) interactionDelegate {

    UIDocumentInteractionController *interactionController = [UIDocumentInteractionController interactionControllerWithURL: fileURL];
    interactionController.delegate = interactionDelegate;
    return interactionController;
}
于 2017-06-19T04:57:13.760 回答
0
NSURL *myURL = [NSURL URLWithString:sampleImageURL];
NSData * imageData = [[NSData alloc] initWithContentsOfURL:myURL];
UIImage *imageToUse = [[UIImage alloc] initWithData:imageData];
NSString *documentDirectory=[NSHomeDirectory() stringByAppendingPathComponent:@"Documents"];
NSString *saveImagePath=[documentDirectory stringByAppendingPathComponent:@"Image.ig"];
[imageData writeToFile:saveImagePath atomically:YES];
NSURL *imageURL=[NSURL fileURLWithPath:saveImagePath];
self.documentController = [UIDocumentInteractionController interactionControllerWithURL:imageURL];
self.documentController.delegate = self;
self.documentController.annotation = [NSDictionary dictionaryWithObjectsAndKeys:[NSString stringWithFormat:@""], @"", nil];
self.documentController.UTI = @"com.instagram.exclusivegram";
[self.documentController presentOpenInMenuFromRect:CGRectMake(1, 1, 1, 1) inView:self.view animated:YES];
于 2020-03-09T12:40:48.687 回答