当我运行这个线程时,我目前收到 NULL 指针异常
public void run() {
long idle = 0;
this.touch();
do {
idle = System.currentTimeMillis() - lastUsed;
Log.d(TAG, "Application is idle for " + idle + " ms");
if ((idle > 5000) && (check == false)) { // Checking For 2 Minutes.
Log.e("AthanAd", "2 minutes over - Show Ad.");
adView = (AdView) view.findViewById(R.id.adView);
adView.loadAd(new AdRequest());
check = true;
}
try {
Thread.sleep(8000); // check every 5 seconds
} catch (InterruptedException e) {
Log.d(TAG, "Waiter interrupted!");
}
if (idle > period) {
idle = 0;
// do something here - e.g. call popup or so
}
} while (!stop);
Log.d(TAG, "Finishing Waiter thread");
}
我在这条线上得到了例外。
adView = (AdView) view.findViewById(R.id.adView);
在应用程序的顶部,我声明了View 视图;但我知道我没有将它与任何观点联系起来。
我的问题是:我怎样才能让视图在屏幕上可见?