javascript - 扩展原型函数而不覆盖它

Question

我需要修复saveParse.Object 库的功能中的错误。但是，当我尝试save在覆盖的原型中调用原始函数时，它会递归循环直到堆栈溢出！

Parse.Object.prototype.save = function (arg1, arg2, arg3) {
    fixIncludedParseObjects(this);

    Parse.Object.prototype.save.call(this, arg1, arg2, arg3); // endless loop
};

如何更改无限循环线以调用解析生成的原始函数？

谢谢！

Answer 1

试试这个：

(function(save) {
  Parse.Object.prototype.save = function (arg1, arg2, arg3) {
    fixIncludedParseObjects(this);
    save.call(this, arg1, arg2, arg3);
  };
}(Parse.Object.prototype.save));

Answer 2

类似于接受的答案，但可能更容易理解

var originalSaveFn = Parse.Object.prototype.save;
Parse.Object.prototype.save = function(arg1, arg2, arg3) {
    fixIncludedParseObjects(this);
    originalSaveFn.call(this, arg1, arg2, arg3);
};

Answer 3

Parse.Object.prototype.save = function (save) {
    return function () {
        fixIncludedParseObjects(this);
        //Remember to return and .apply arguments when proxying
        return save.apply(this, arguments);
    };
}(Parse.Object.prototype.save);