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我正在运行一个 PHP 脚本来从 HTML 表单上传文件，重命名它们并将它们放在我的服务器上。它正在上传和重命名，但是现在每个文件名都以“Array”一词开头，
即：ArrayTest Document v1.0.pdf
我相当确信它不是我的$newfn变量，因为我在表格中显示它并且它没有显示出来。

//This gets all the other information from the form
$name=$_POST['docname'];
$version=$_POST['docver'];
$date=$_POST['docdate'];
$type=$_POST['doctype'];
$author=$_POST['docauth'];
$file=$_FILES['uploaded']['name'];

//target directory is assigned
$target = $directory;
$target = $target . basename($file) ;

//grab file extension
$filetypes = array(
'image/png' => '.png',
'image/gif' => '.gif',
'image/jpeg' => '.jpg',
'image/bmp' => '.bmp',
'application/pdf' => '.pdf');
$ext = $filetypes[$_FILES['uploaded']['type']];

//generate new filename variable "name v??.xxx"
$newfn = $name . ' ' . 'v' . $version . $ext;

//Check to see if file exists
if (file_exists($directory . $file))
{
echo $_FILES["uploaded"]["name"] . " already exists. ";
}
else
{
//if its a new file, change name and upload
    if (move_uploaded_file($_FILES["uploaded"]["tmp_name"],
        $directory . $_FILES["uploaded"] . $newfn))
        {
        echo "The file ". basename($file). " has been uploaded";
        }
        else
        {
        echo "Sorry, there was a problem uploading your file.";
        }
}

我觉得它与命令$FILES['uploaded']中的我的部分有关move_uploaded_file。我试过谷歌搜索，但只要我提到“数组”，我的谷歌搜索结果就完全不同了。

好的，多亏了下面我解决了它。对于将来的任何人，我删除了整个$_FILES数组，因此代码读取为

//if its a new file, change name and upload
if (move_uploaded_file($_FILES["uploaded"]["tmp_name"],
    $directory . $newfn))

现在所有内容都以正确的名称结构上传。谢谢。

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2 回答 2

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应该

move_uploaded_file($_FILES["uploaded"]["tmp_name"],$directory . $_FILES["uploaded"]["name"] . $newfn)

您忘记在 $_FILES["uploaded"] 之后包含 ["name"]

于 2012-07-08T06:49:31.070 回答
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在您的 move_uploaded_file 中，您使用整个$_FILE['uploaded']数组作为名称，而不仅仅是文件名。一个小调整：

if (move_uploaded_file($_FILES["uploaded"]["tmp_name"],
        $directory . $_FILES["uploaded"]["name"] . $newfn))
        {

你应该一切都好。

于 2012-07-08T06:50:01.967 回答