php - 获取 SimpleXML 错误

Question

我正在尝试回显位于引号之间的文本<head_1 data="Superhero"/>

XML 文件如下所示：

<?xml version="1.0"?>
<nowplaying version="1.1">
    <playing_now>
        <rbds_text data="SUPERHERO by Family Force 5"/>
        <result>
            <type data="song"/>
            <head_1 data="Superhero"/>
            <head_2 data="Family Force 5"/>
            <head_url data="song/Family_Force_5/Superhero.html"/>
            <foot_1 data="III.V - EP"/>
            <foot_2 data="Family Force 5"/>
            <foot_url data="album/Family_Force_5/III.V_-_EP.html"/>
            <image_50 data="/images/music/thumbs/familyforce5-iiivep.jpg"/>
            <image_200 data="/images/music/familyforce5-iiivep.jpg"/>
        </result>
    </playing_now>
</nowplaying>

我当前的 PHP 文件如下所示，但出现错误：

<?php
include 'playing-now/api.html';

$nowplaying = new SimpleXMLElement($xmlstr);

echo $nowplaying->playing_now->result->head_1;"
?>

Answer 1

echo $nowplaying->playing_now->result->head_1['data'];

如果您遇到任何错误，则可能在名称上。您应该能够像这样逃脱它们：

echo $nowplaying->{'playing_now'}->result->{'head_1'}['data'];