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嗨,我有这段代码来搜索 n 元树,但它工作正常,我不知道在搜索 n4 和 n5 时它有什么问题,它返回 n3 有什么问题? 在此处输入图像描述

public FamilyNode findNodeByName(FamilyNode nodeName ){
       if(this.name.equals(nodeName.name)){
          // We found a node named nodeName, return it
          return this;
       } 
       // That's not me that you are looking for, let's see my kids

           for(FamilyNode child : this.children){
            if(child.findNodeByName(nodeName) != null) 
              return child;
                // We found what we are looking, just return from here
            //    return child;

       }
       // Finished looping over all nodes and did not find any, return null
       return null;
    }
4

1 回答 1

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原因是你交还了找到节点的节点。一旦找到一个节点,就需要返回这个节点,如果找到 a 的父节点FamilyNode需要返回 found FamilyNodefound检查变量做了什么。

你需要做这样的事情:

FamilyNode found = child.findNodeByName(nodeName);
if(found != null) 
    return found;

整个方法将如下所示:

public FamilyNode findNodeByName(FamilyNode nodeName ){
    if(this.name.equals(nodeName.name)){
        return this;
    } 
    for(FamilyNode child : this.children){
        FamilyNode found = child.findNodeByName(nodeName);
        if(found != null) 
            return found;
    }
    return null;
}
于 2012-07-07T07:50:17.057 回答