1

我正在尝试从 Web 服务解析和获取值。问题是 Web 服务具有相同的元素名称标签，这些标签正在创建要解析的问题，因为我想获取它们的值但它们具有相同的名称所以我很难将它们作为本地名称提及。

 <countryBean>
        <id>236</id>
        <name>United State</name>
    </countryBean>
    <secutiryQuestion1>
        <id>2</id>
        <question>What was your dream job as a child?</question>
    </secutiryQuestion1>
    <secutiryQuestion2>
        <id>4</id>
        <question>What is the name, breed, and color of your pet?</question>
    </secutiryQuestion2>
    <stateBean>
        <country>236</country>
        <id>5</id>
        <name>California</name>
    </stateBean>
    <statusBean>
        <id>1</id>
        <name>Active</name>
    </statusBean>

我想在不同的变量中获取 ID 标签和其他相邻标签（如名称、问题）的值。这里有 5 个 ID 标签。

我的课程代码就像

public class XmlParser extends DefaultHandler {

        public RestfullResponse tempResponse = null;
        String currentValue = null;
        int ServiceType =0;

        @Override
        public void startElement(String uri, String localName, String qName,
                Attributes attributes) throws SAXException {
            if(localName.equalsIgnoreCase("countryBean")){
                tempResponse=new RestfullResponse();

                }           

        }


        /* (non-Javadoc)
         * @see org.xml.sax.helpers.DefaultHandler#endElement(java.lang.String, java.lang.String, java.lang.String)
         */
        @Override
        public void endElement(String uri, String localName, String qName)
                throws SAXException {
            if(ServiceType == 1)
            {
                if(localName.equalsIgnoreCase("id")){
                    tempResponse.setCountryId(currentValue);
                }
                if(localName.equalsIgnoreCase("name")){
                    tempResponse.setCountryName(currentValue);
                }

                if(localName.equalsIgnoreCase("id")){
                    tempResponse.setStateId(currentValue);
                }
                if(localName.equalsIgnoreCase("question")){
                    tempResponse.setstateBean(currentValue);
                }

                if(localName.equalsIgnoreCase("Id")){
                    tempResponse.setStatusId(currentValue);
                }
                if(localName.equalsIgnoreCase("requestSuccess")){
                    tempResponse.setStatus(currentValue);
                }
            }
        }

        @Override
        public void characters(char[] ch, int start, int length)
                throws SAXException {
            currentValue = new String(ch, start, length);
        }

        public RestfullResponse getResponse(){
            return tempResponse;
        }
}

请帮助将它们存储在

String CountryName= "";
String CountryId = "";
String Statename = "";
String StateId ="";
String Status = "";
String StatusId = "";
String Username ="";
String SecurityQuestion = "";
String SecurityQuestionId = "";
4

2 回答 2

2

添加布尔变量isCountryBean；

boolean isCountryBean = false , isSecurityQuestion1 = false;

在 startElement(....) 中写：

if(localName.equalsIgnoreCase("countryBean")){
    isCountryBean = true;
    // other stuff
} else if (localName.equalsIgnoreCase("secutiryQuestion1")){
    isSecurityQuestion1 = true;
    isCountryBean = false;
}

在 endElement(...) 检查：

if(localName.equalsIgnoreCase("id")){
    if(isCountryBean){
        tempResponse.setCountryId(currentValue); 
     }
}
if(localName.equalsIgnoreCase("name")){
    if(isCountryBean){
        isCountryBean = false;
        tempResponse.setCountryName(currentValue);

     }
}

为其他最外向的标签执行此操作。希望它会帮助你。

于 2012-07-06T13:53:10.563 回答
1

您需要维护stack of root nodes.

取一个类型的变量String root并维护一个stack of root element.

内部 startElement 方法：

public void startElement(String namespaceURI, String localName, String qName, Attributes atts) throws SAXException,
            IllegalArgumentException
{

   // call to abstract method
   onStartElement(namespaceURI, localName, qName, atts);

   // Keep the trace of the root nodes
   if (root.length() > 0)
   {
    root= root.concat(",");
   }
   root= root.concat(localName);
}

内部 endElement 方法：

public void endElement(String namespaceURI, String localName, String qName) throws SAXException
{
   // remove the end element from stack of root elements
   int index = root.lastIndexOf(',');
   if (index > 0)
   {
    root= root.substring(0, index);
   }
   onEndElement(namespaceURI, localName, qName);
}
于 2012-07-06T13:15:48.707 回答