1

我使用System.Diagnostic.Process类在使用 .Net WCF Web 服务的服务器 PC 上启动进程。他们开始顺利，我可以看到他们从任务管理器运行，但没有显示窗口。你们认为我怎样才能克服这个问题？

4

3 回答 3

3

如果你想显示一个 GUI 并且用户能够与之交互，你必须启动一个交互过程。您的 Web 服务目前可能不是这种情况。

请参阅启动 Windows 服务并启动 cmd

于 2012-07-06T12:13:09.453 回答
1

你不应该这样做，但是......

您可以在当前会话中以用户身份启动程序

IntPtr UserTokenHandle = IntPtr.Zero;
WTSQueryUserToken ( WTSGetActiveConsoleSessionId(), ref UserTokenHandle);

PROCESS_INFORMATION ProcInfo = new PROCESS_INFORMATION();
STARTUPINFOW StartInfo = new STARTUPINFOW();
StartInfo.cb = Convert.ToUInt32(System.Runtime.InteropServices.Marshal.SizeOf(StartInfo));


CreateProcessAsUser ( UserTokenHandle, @"C:\dir\MyApp.exe",
    IntPtr.Zero,
    IntPtr.Zero,
    IntPtr.Zero,
    false,
    0,
    IntPtr.Zero,
    null,
    ref StartInfo,
    ref ProcInfo);

if (!(UserTokenHandle == IntPtr.Zero))
{
    CloseHandle ( UserTokenHandle);
}

所需的导入和结构：

[DllImport("kernel32.dll", EntryPoint = "WTSGetActiveConsoleSessionId", SetLastError = true)]
public static extern uint WTSGetActiveConsoleSessionId ();

[DllImport("Wtsapi32.dll", EntryPoint = "WTSQueryUserToken", SetLastError = true)]
[return: MarshalAs(UnmanagedType.Bool)]
public static extern bool WTSQueryUserToken ( uint SessionId, ref IntPtr phToken );

[DllImport("kernel32.dll", EntryPoint = "CloseHandle", SetLastError = true)]
[return: MarshalAs(UnmanagedType.Bool)]
public static extern bool CloseHandle ( [InAttribute()]
    IntPtr hObject );

[DllImport("advapi32.dll", EntryPoint = "CreateProcessAsUserW", SetLastError = true)]
[return: MarshalAs(UnmanagedType.Bool)]
public static extern bool CreateProcessAsUser (
    [InAttribute()]
    IntPtr hToken,
    [InAttribute(), MarshalAs(UnmanagedType.LPWStr)]
    string lpApplicationName, System.IntPtr lpCommandLine,
    [InAttribute()]
    IntPtr lpProcessAttributes,
    [InAttribute()]
    IntPtr lpThreadAttributes,
    [MarshalAs(UnmanagedType.Bool)]
    bool bInheritHandles, uint dwCreationFlags,
    [InAttribute()]
    IntPtr lpEnvironment,
    [InAttribute(), MarshalAsAttribute(UnmanagedType.LPWStr)]
    string lpCurrentDirectory,

ref STARTUPINFOW lpStartupInfo,

ref PROCESS_INFORMATION lpProcessInformation );

[StructLayout(LayoutKind.Sequential)]
public struct SECURITY_ATTRIBUTES
{
    public uint nLength;
    public IntPtr lpSecurityDescriptor;
    [MarshalAs(UnmanagedType.Bool)]
    public bool bInheritHandle;
}

[StructLayout(LayoutKind.Sequential)]
public struct STARTUPINFOW
{
    public uint cb;
    [MarshalAs(UnmanagedType.LPWStr)]
    public string lpReserved;
    [MarshalAs(UnmanagedType.LPWStr)]
    public string lpDesktop;
    [MarshalAs(UnmanagedType.LPWStr)]
    public string lpTitle;
    public uint dwX;
    public uint dwY;
    public uint dwXSize;
    public uint dwYSize;
    public uint dwXCountChars;
    public uint dwYCountChars;
    public uint dwFillAttribute;
    public uint dwFlags;
    public ushort wShowWindow;
    public ushort cbReserved2;
    public IntPtr lpReserved2;
    public IntPtr hStdInput;
    public IntPtr hStdOutput;
    public IntPtr hStdError;
}

[StructLayout(LayoutKind.Sequential)]
public struct PROCESS_INFORMATION
{
    public IntPtr hProcess;
    public IntPtr hThread;
    public uint dwProcessId;
    public uint dwThreadId;
}
于 2012-07-06T12:21:10.937 回答
0

您在谈论 Web 服务，因此它可能也作为 Windows 服务运行？在这种情况下，您可以启动流程，但永远不会看到任何表单。

Windows 服务旨在在您的计算机上运行，​​即使没有用户登录。因此，它永远不知道在哪里显示您要运行的应用程序！

您可以摆弄一个名为“允许与桌面交互”（或类似的东西）的设置，但服务并不意味着以这种方式使用。

于 2012-07-06T12:07:54.503 回答