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我想解析一个字符串来替换一些元素。
如果我的字符串包含一个，<ol>那么我想解析<li>元素以用数字替换它们。

我知道我可以检查rangeOfString包含的字符串。 

if ([myString rangeOfString:@"<ol>"].location != NSNotFound) {
    //Do stuff here  
}

我怎样才能只解析<ol>和</ol>元素之间？

编辑1：这是我的解决方案 

- (NSString *)parseOrderedList:(NSString *)str {


NSMutableString *html = [NSMutableString stringWithCapacity:[str length]];

NSScanner *scanner = [NSScanner scannerWithString:str];
NSString *tempText = nil;

while (![scanner isAtEnd])
{
    [scanner scanUpToString:@"<ol>" intoString:&tempText];
    [scanner scanUpToString:@"</ol>" intoString:&tempText];


    if (tempText != nil) {
        [html appendString:tempText];
        html = [[[html stringByReplacingOccurrencesOfString:@"</li>" withString:@" "] mutableCopy] autorelease];

            while ([html rangeOfString:@"<li>"].location != NSNotFound) {
                html = [[[html stringByReplacingOccurrencesOfString:@"<li>" withString:[NSString stringWithFormat:@"%i.", i]] mutableCopy] autorelease];
                i++;
            }

    }


    if (![scanner isAtEnd])
        [scanner setScanLocation:[scanner scanLocation] + 0];

    tempText = @" ";

}

return html;
}

但是我该如何更换

  • 与当前循环计数？每次第一次计数时我都会得到。

    • 4

    1 回答 1

    1

    做这个

    NSString * aString = @"your string";
NSMutableArray *substrings = [NSMutableArray alloc]init];
NSScanner *scanner = [NSScanner scannerWithString:aString];
[scanner scanUpToString:@"<ol>" intoString:nil]; // Scan all characters before <ol>
while(![scanner isAtEnd]) 
{
  NSString *substring = nil;
  [scanner scanString:@"<ol>" intoString:nil]; // Scan the <ol> character
  if([scanner scanUpToString:@"</ol>" intoString:&substring]) 
  {
  // If the space immediately followed the <ol>, this will be skipped
  [substrings addObject:substring];
  }
 [scanner scanUpToString:@"<ol>" intoString:nil]; // Scan all characters before next <ol>
}

    你在 nsmutablearray 中有字符串，可以用来替换你的字符串

    可以对其他标签重复相同的方法

    于 2012-07-06T10:16:57.740 回答