mysql - 将 SELECT AS 与值进行比较

Question

有了这个查询

SELECT least(col1, col2, col3) AS fancyTitle
FROM table
ORDER BY fancyTitle

例如，如何将fancyTitle其与一个值进行比较，以便我只输出高于 100 的值。

Answer 1

+您必须在您想要的列之间放置运算符SUM()。您不能将逗号分隔的列表传递给SUM()

你可以做：

SELECT id, SUM(col1 + col2+ col3) AS fancyTitle
FROM tbl
GROUP BY id
HAVING SUM(col1 + col2 + col3) > 100

Answer 2

标准 SQL：

SELECT SUM(col1 + col2 + col3) AS fancyTitle
FROM table
HAVING SUM(col1 + col2 + col3) > 100 ;

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MySQL 也允许这样做（不推荐，但它会这样做）：

SELECT SUM(col1 + col2 + col3) AS fancyTitle
FROM table
HAVING fancyTitle > 100 ;

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或者也许你只想要这个：

SELECT col1 + col2 + col3 AS fancyTitle
FROM table
WHERE col1 + col2 + col3 > 100 
ORDER BY fancyTitle ;

Answer 3

试试这个 ：

SELECT sum(col1, col2, col3) AS fancyTitle
FROM table where sum(col1, col2, col3) > 100
GROUP BY fancyTitle;