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我正在制作一个将两个数据库合并在一起的程序......我可以使用以下代码将 excel 电子表格导入 DataGridView：

     string connectionString = @"Provider=Microsoft.Jet.OLEDB.4.0;Data Source=C:\test.xls;Extended Properties=""Excel 8.0;HDR=YES;IMEX=1""";

                DbProviderFactory factory = DbProviderFactories.GetFactory("System.Data.OleDb");

                DbDataAdapter adapter = factory.CreateDataAdapter();

                DbCommand selectCommand = factory.CreateCommand();
                selectCommand.CommandText = "SELECT * FROM [All Carpets to Excel$]";

                DbConnection connection = factory.CreateConnection();
                connection.ConnectionString = connectionString;

                selectCommand.Connection = connection;

                adapter.SelectCommand = selectCommand;

                data = new DataSet();

                adapter.Fill(data);

                dataGridView1.DataSource = data.Tables[0].DefaultView;

我遇到的问题是我试图找到一种方法将源文件更改为对话框返回的路径。我有一个包含文件路径的字符串文件。如何将其合并到连接字符串中？

或者也许有更好的方法来做到这一点？

谢谢！

卢克

4

2 回答 2

2

使用OleDbConnectionStringBuilder该类来修改您的连接字符串。

string fileName = "your path to the excel.xls"; // From the dialog box.

OleDbConnectionStringBuilder connStringBuilder =
    new OleDbConnectionStringBuilder();

connStringBuilder.DataSource = fileName;  // Set path to excel file
connStringBuilder.Provider = "Microsoft.Jet.OLEDB.4.0";
connStringBuilder.Add("Extended Properties", "Excel 8.0;HDR=YES;IMEX1");        

...

// Get the connection string from the builder.
connection.ConnectionString = connStringBuilder.ConnectionString;
于 2012-07-05T18:00:07.633 回答
0

您只需要 Microsoft.Office.Interop.Excel 并将其与数据表和数据集相结合。

    Excel.Workbook ExWorkbook;
    Excel.Worksheet ExWorksheet;
    Excel.Range ExRange;
    Excel.Application ExObj = new Excel.Application();

    DataTable dt = new DataTable("dataTable");
    DataSet dsSource = new DataSet("dataSet");
    dt.Reset();

    openFileDialog1.Filter = "Excel Files|*.xls;*.xlsx;*.xlsm";
    DialogResult result = openFileDialog1.ShowDialog();

    if (result == DialogResult.OK) // Test result.
    {
        ExWorkbook = ExObj.Workbooks.Open(openFileDialog1.FileName, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value);
        ExWorksheet = (Excel.Worksheet)ExWorkbook.Sheets.get_Item(1);
        ExRange = ExWorksheet.UsedRange;

        for (int Cnum = 1; Cnum <= ExRange.Columns.Count; Cnum++)
        {
            dt.Columns.Add(new DataColumn((ExRange.Cells[1, Cnum] as Excel.Range).Value2.ToString()));
        }
        dt.AcceptChanges();

        string[] columnNames = new String[dt.Columns.Count];
        for (int i = 0; i < dt.Columns.Count; i++)
        {
            columnNames[0] = dt.Columns[i].ColumnName;
        }

        for (int Rnum = 2; Rnum <= ExRange.Rows.Count; Rnum++)
        {
            DataRow dr = dt.NewRow();
            for (int Cnum = 1; Cnum <= ExRange.Columns.Count; Cnum++)
            {
                if ((ExRange.Cells[Rnum, Cnum] as Excel.Range).Value2 != null)
                {
                    dr[Cnum - 1] = (ExRange.Cells[Rnum, Cnum] as Excel.Range).Value2.ToString();
                }
            }
            dt.Rows.Add(dr);
            dt.AcceptChanges();
        }
        ExWorkbook.Close(true, Missing.Value, Missing.Value);
        ExObj.Quit();

        dataGridView1.DataSource = dt;
于 2014-01-30T02:48:57.980 回答