我在使用 Canvas 绘制数学方程式和文本以及在屏幕底部使用文本框输入结果数据时遇到问题。在我当前的设置中,我可以有按钮和文本框,或者方程和变量名称。这是我的java类代码
package com.soraingraven.suprRef;
import java.io.IOException;
import java.io.InputStream;
import android.app.Activity;
import android.content.Context;
import android.content.res.AssetManager;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.graphics.Canvas;
import android.graphics.Color;
import android.graphics.Paint;
import android.graphics.Typeface;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.view.Window;
import android.view.WindowManager;
public class PerfectGasLaw extends Activity {
class RenderView extends View {
//For the Text
Paint paint;
Typeface font;
//For the pics
Bitmap PGL;
public RenderView(Context context) {
super(context);
paint = new Paint();
//Attempt to load the bitmaps
try {
AssetManager assetManager = context.getAssets();
InputStream inputStream = assetManager.open("PerfGasLaw.png");
BitmapFactory.Options options = new BitmapFactory.Options();
options.inPreferredConfig = Bitmap.Config.ARGB_4444;
PGL = BitmapFactory.decodeStream(inputStream, null, options);
inputStream.close();
Log.d("BitmapText", "bobargb8888.png format: " + PGL.getConfig());
} catch (IOException e) {
e.printStackTrace();
} finally {
//we should really close our input streams here.
}
}
//Drawing text and pics
protected void onDraw(Canvas canvas) {
paint.setColor(Color.BLUE);
paint.setTypeface(font);
paint.setTextSize(32);
paint.setTextAlign(Paint.Align.LEFT);
canvas.drawText("P = Pressure in Atmospheres", 25, 350, paint);
canvas.drawText("V = Volume in Liters", 25, 400, paint);
canvas.drawText("n = Number of moles", 25, 450, paint);
canvas.drawText("R = Gas Constant", 25, 500, paint);
canvas.drawText(" - (0.0821 Liter-Atmospheres / K / mole)", 50, 550, paint);
canvas.drawText("T = Temperature in K", 25, 600, paint);
canvas.drawText("If Constant Pressure - V1/V2 = T1/T2", 25, 650, paint);
canvas.drawText("If Constant Temperature - P1/P2 = V2/V1", 25, 700, paint);
canvas.drawText("If Constant Volume - P1/P2 = T1/T2", 25, 750, paint);
canvas.drawBitmap(PGL, 25, 25, null);
invalidate();
}
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
setContentView(new RenderView(this));
}
}
和 XML
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="horizontal" >
<EditText
android:id="@+id/edit_message"
android:layout_width="0dp"
android:layout_height="wrap_content"
android:layout_gravity="bottom"
android:layout_weight="1"
android:ems="10"
android:hint="@string/edit_message" >
<requestFocus />
</EditText>
<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_gravity="bottom"
android:text="@string/button_send" />
</LinearLayout>
请协助我执行此操作。此外,如果有人能告诉我如何从这样的文本字段中获取输入,那将会很有帮助。此外,我正在尝试使用尽可能少的 XML 来做到这一点。