所以我使用 apache HttpComponents 来处理 java 中的 http 请求。现在我想重用DefaultHttpClient
,根据这个例子应该有什么可能:http ://wiki.apache.org/HttpComponents/QuickStart 。该示例本身给出了一个 ssl 错误,因此我对其进行了一些修改和简化。现在我总是得到一个org.apache.http.client.ClientProtocolException
这是我的示例程序,基本上我只是请求 2 个网页使用相同的DefaultHttpClient
.
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStream;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
public class ClientFormLogin {
public static void main(String[] args) throws Exception {
DefaultHttpClient httpclient = new DefaultHttpClient();
//Handle first request.
HttpGet httpget = new HttpGet("http://tweakers.net/nieuws/82969/amazon-nederland-opent-digitale-deuren-in-september.html");
HttpResponse response = httpclient.execute(httpget);
System.out.println("Execute finished");
HttpEntity entity = response.getEntity();
String page = readInput(entity.getContent());
System.out.println("Request one finished without problems!");
//Handle second request
HttpGet httpost = new HttpGet("http://gathering.tweakers.net/forum/list_messages/1506977/last");
response = httpclient.execute(httpost);
entity = response.getEntity();
page = readInput(entity.getContent());
System.out.println("Request two finished without problems!");
}
private static String readInput(InputStream in) throws IOException {
ByteArrayOutputStream out = new ByteArrayOutputStream();
byte bytes[] = new byte[1024];
int n = in.read(bytes);
while (n != -1) {
out.write(bytes, 0, n);
n = in.read(bytes);
}
return new String(out.toString());
}
}
运行我的示例时,出现以下错误
Request one finished without problems!
Exception in thread "main" org.apache.http.client.ClientProtocolException
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:909)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:805)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:784)
at ClientFormLogin.main(ClientFormLogin.java:29)
Caused by: org.apache.http.HttpException: Unable to establish route: planned = {}->http://gathering.tweakers.net; current = {}->http://tweakers.net
at org.apache.http.impl.client.DefaultRequestDirector.establishRoute(DefaultRequestDirector.java:842)
at org.apache.http.impl.client.DefaultRequestDirector.tryConnect(DefaultRequestDirector.java:645)
at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:480)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:906)
... 3 more
任何人都可以给我一些指示如何解决这个问题,除了DefaultHttpClient
为每个请求使用一个新的。
编辑
我刚刚发现如果我留在同一个域上我没有问题,所以:
page1: 'http://tweakers.net/nieuws/82969/amazon-nederland-opent-digitale-deuren-in-september.html'
page2: 'http://tweakers.net/nieuws/82973/website-nujij-belandt-op-zwarte-lijst-google-door-malware.html'
如果我必须这样做,我没有问题:
page1: 'http://tweakers.net/nieuws/82969/amazon-nederland-opent-digitale-deuren-in-september.html'
page2: 'http://gathering.tweakers.net/forum/list_messages/1506076/last'
我得到了错误。
Ofc 我在发布我的问题后一分钟看到了这个。除非有人能告诉我如何去 2 个具有相同问题的独立域,否则DefaultHttpClient
我的问题已经得到解答。