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我有一个包含这种格式的字符串的文件：

ACHMU)][2:s,161,(ACH Payment Sys Menus - Online Services)][3:c,1,(M)][4:c,1,(N)]
ACLSICZ)][2:s,161,(Report for Auto Closure)][3:c,1,(U)][4:c,1,(N)]
ACMPS)][2:s,161,(Account Maintenance-Pre-shipment Account)][3:c,1,(U)][4:c,1,(N)]
ACNPAINT)][2:s,161,(Interest Run For NPA Accounts)][3:c,1,(U)][4:c,1,(N)]

我需要拆分字符串，以便我拥有这种格式的数据：

ACHMU (ACH Payment Sys Menus - Online Services)
ACLSICZ (Report for Auto Closure)......

基本上，我想删除最后的 ")[2:s,161" 部分和 "][3:c,1,(M)][4:c,1,(N)]" 。拆分字符串对我有帮助吗？以下方法已经失败：

FileInputStream fs = new FileInputStream(C:/Test.txt);
BufferedReader br  = new BufferedReader(new InputStreamReader(fs));
String str;
while((str = br.readLine()) != null){
    String[] split = str.Split(")[2:s,161,")
}

请帮我把垃圾放在中间和最后。

4

4 回答 4

3

直接的方式，使用substring()and indexOf()：

String oldString = "ACHMU)][2:s,161,(ACH Payment Sys Menus - Online Services)][3:c,1,(M)][4:c,1,(N)]";
String firstPart = oldString.substring(0, oldString.indexOf(")")); // ACHMU
String secondPart = oldString.substring(oldString.indexOf("(")); // (ACH Payment Sys Menus - Online Services)][3:c,1,(M)]
String newString = firstPart + " " + secondPart.substring(0, secondPart.indexOf(")") + 1); // ACHMU (ACH Payment Sys Menus - Online Services)
System.out.print(newString);

输出：

ACHMU（ACH 支付系统菜单 - 在线服务）

于 2012-07-05T11:47:04.033 回答
2

您可以使用

str.replaceFirst("(.*?)\\)\\].*?(\\(.*?\\))\\].*", "$1 $2");
于 2012-07-05T11:45:34.517 回答
2 
FileInputStream fs = new FileInputStream(C:/Test.txt);
BufferedReader br  = new BufferedReader(new InputStreamReader(fs));
String str;
String newStr;
String completeNewStr="";
while((str = br.readLine()) != null)
{
    newStr = str.replace(")][2:s,161,"," ");
    newStr = str.replace("][3:c,1,(M)][4:c,1,(N)]","");
    completeNewStr+=newStr;
}

// completeNewStr is your final string
于 2012-07-05T11:52:00.083 回答
1

如果您要替换的字符串始终为 "[2:s,161," ，请在可接受的情况下将其替换为空字符串或空格。同样，对于其他字符串也是如此。

str.replace("[2:s,161,", '');
于 2012-07-05T11:51:21.887 回答